AQA AS Paper 1 2020 June — Question 11 1 marks

Exam BoardAQA
ModuleAS Paper 1 (AS Paper 1)
Year2020
SessionJune
Marks1
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicForces, equilibrium and resultants
TypeMotion with friction on horizontal surface
DifficultyEasy -1.8 This is a straightforward one-mark mechanics question requiring only F=ma and simple subtraction (14 - 55×0.2 = 3N). It's a routine calculation with multiple-choice format, making it significantly easier than average A-level questions which typically require multi-step problem-solving.
Spec3.03c Newton's second law: F=ma one dimension

A go-kart and driver, of combined mass 55 kg, move forward in a straight line with a constant acceleration of \(0.2\text{ m s}^{-2}\) The total driving force is 14 N Find the total resistance force acting on the go-kart and driver. Circle your answer. [1 mark] 0N 3N 11N 14N

Question 11:
AnswerMarks Guidance
11Circles correct answer 1.1b
Total1
QMarking Instructions AO
Question 11:
11 | Circles correct answer | 1.1b | B1 | 3 N
Total | 1
Q | Marking Instructions | AO | Marks | Typical Solution
A go-kart and driver, of combined mass 55 kg, move forward in a straight line with a constant acceleration of $0.2\text{ m s}^{-2}$

The total driving force is 14 N

Find the total resistance force acting on the go-kart and driver.

Circle your answer.
[1 mark]

0N    3N    11N    14N

\hfill \mbox{\textit{AQA AS Paper 1 2020 Q11 [1]}}