Easy -1.8 This is a very straightforward derivation of a standard kinematic equation from a velocity-time graph using basic gradient concepts. It requires only recognizing that acceleration equals gradient (change in velocity over time), which is fundamental GCSE/AS mechanics with minimal algebraic manipulation. The question essentially guides students through showing a formula they should already know.
An object is moving in a straight line, with constant acceleration \(a\text{ m s}^{-2}\), over a time period of \(t\) seconds.
It has an initial velocity \(u\) and final velocity \(v\) as shown in the graph below.
\includegraphics{figure_13}
Use the graph to show that
$$v = u + at$$ [3 marks]
An object is moving in a straight line, with constant acceleration $a\text{ m s}^{-2}$, over a time period of $t$ seconds.
It has an initial velocity $u$ and final velocity $v$ as shown in the graph below.
\includegraphics{figure_13}
Use the graph to show that
$$v = u + at$$ [3 marks]
\hfill \mbox{\textit{AQA AS Paper 1 2020 Q13 [3]}}