CAIE Further Paper 2 2023 June — Question 1 5 marks

Exam BoardCAIE
ModuleFurther Paper 2 (Further Paper 2)
Year2023
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSimultaneous equations
TypeSystem of three linear equations
DifficultyStandard +0.8 This question requires understanding of linear dependence, matrix rank, and geometric interpretation of degenerate systems. While solving 3×3 systems is standard, recognizing non-uniqueness (determinant = 0 or row operations showing dependence) and proving consistency (showing the equations represent three planes meeting in a line) requires deeper conceptual understanding beyond routine calculation, placing it moderately above average difficulty.
Spec4.03l Singular/non-singular matrices4.03r Solve simultaneous equations: using inverse matrix

1
  1. Show that the system of equations $$\begin{array} { r } x + 2 y + 3 z = 1 \\ 4 x + 5 y + 6 z = 1 \\ 7 x + 8 y + 9 z = 1 \end{array}$$ does not have a unique solution.
  2. Show that the system of equations in part (a) is consistent. Interpret this situation geometrically.

Question 1:
Part (a)
\[\begin{vmatrix} 1 & 2 & 3 \\ 4 & 5 & 6 \\ 7 & 8 & 9 \end{vmatrix} = (5\times9-8\times6)-2(4\times9-7\times6)+3(4\times8-7\times5)\]
\[= -3+12-9=0\]
AnswerMarks Guidance
AnswerMarks Guidance
Shows determinant is zero or uses row operations to obtain e.g. \(x+2y+3z=1\), \(y+2z=1\)M1 A1 Shows that determinant is zero or row operations to obtain e.g. \(x+2y+3z=1\), \(y+2z=1\)
[2]
Part (b)
\[x+2y+3z=1,\]
\[4x+5y+6z=1, \Rightarrow z=\tfrac{1}{3}(1-x-2y)\Rightarrow y=-2x-1\]
\[7x+8y+9z=1,\]
The three planes form a sheaf.
AnswerMarks Guidance
AnswerMarks Guidance
Uses *all three* equations to reduce to one equation with two unknownsM1 A1 Reducing to two equations scores M1 A0
The three planes form a sheafB1 Accept clear sketch or the three planes intersect along a common line
[3]
## Question 1:

### Part (a)

$$\begin{vmatrix} 1 & 2 & 3 \\ 4 & 5 & 6 \\ 7 & 8 & 9 \end{vmatrix} = (5\times9-8\times6)-2(4\times9-7\times6)+3(4\times8-7\times5)$$

$$= -3+12-9=0$$

| Answer | Marks | Guidance |
|--------|-------|----------|
| Shows determinant is zero or uses row operations to obtain e.g. $x+2y+3z=1$, $y+2z=1$ | **M1 A1** | Shows that determinant is zero or row operations to obtain e.g. $x+2y+3z=1$, $y+2z=1$ |
| | **[2]** | |

---

### Part (b)

$$x+2y+3z=1,$$
$$4x+5y+6z=1, \Rightarrow z=\tfrac{1}{3}(1-x-2y)\Rightarrow y=-2x-1$$
$$7x+8y+9z=1,$$

The three planes form a sheaf.

| Answer | Marks | Guidance |
|--------|-------|----------|
| Uses *all three* equations to reduce to one equation with two unknowns | **M1 A1** | Reducing to two equations scores M1 A0 |
| The three planes form a sheaf | **B1** | Accept clear sketch or the three planes intersect along a common line |
| | **[3]** | |
1
\begin{enumerate}[label=(\alph*)]
\item Show that the system of equations

$$\begin{array} { r } 
x + 2 y + 3 z = 1 \\
4 x + 5 y + 6 z = 1 \\
7 x + 8 y + 9 z = 1
\end{array}$$

does not have a unique solution.
\item Show that the system of equations in part (a) is consistent. Interpret this situation geometrically.
\end{enumerate}

\hfill \mbox{\textit{CAIE Further Paper 2 2023 Q1 [5]}}