AQA FP2 2013 January — Question 7 9 marks

Exam BoardAQA
ModuleFP2 (Further Pure Mathematics 2)
Year2013
SessionJanuary
Marks9
PaperDownload PDF ↗
TopicProof by induction
TypeProve divisibility
DifficultyStandard +0.8 This FP2 question requires algebraic manipulation to show a difference is divisible by 9, then a formal induction proof (non-trivial base case and inductive step), followed by a deductive step using the proven result. While the algebra is manageable, the multi-part structure, proof by induction requirement, and final divisibility deduction make this moderately challenging—harder than routine A-level questions but not requiring exceptional insight.
Spec4.01a Mathematical induction: construct proofs4.06b Method of differences: telescoping series

The polynomial \(\text{p}(n)\) is given by \(\text{p}(n) = (n-1)^3 + n^3 + (n+1)^3\).
    1. Show that \(\text{p}(k+1) - \text{p}(k)\), where \(k\) is a positive integer, is a multiple of 9. [3 marks]
    2. Prove by induction that \(\text{p}(n)\) is a multiple of 9 for all integers \(n \geqslant 1\). [4 marks]
  1. Using the result from part (a)(ii), show that \(n(n^2 + 2)\) is a multiple of 3 for any positive integer \(n\). [2 marks]

The polynomial $\text{p}(n)$ is given by $\text{p}(n) = (n-1)^3 + n^3 + (n+1)^3$.

\begin{enumerate}[label=(\alph*)]
\item 
\begin{enumerate}[label=(\roman*)]
\item Show that $\text{p}(k+1) - \text{p}(k)$, where $k$ is a positive integer, is a multiple of 9. [3 marks]

\item Prove by induction that $\text{p}(n)$ is a multiple of 9 for all integers $n \geqslant 1$. [4 marks]
\end{enumerate}

\item Using the result from part (a)(ii), show that $n(n^2 + 2)$ is a multiple of 3 for any positive integer $n$. [2 marks]
\end{enumerate}

\hfill \mbox{\textit{AQA FP2 2013 Q7 [9]}}