OCR MEI FP1 2006 June — Question 9 13 marks

Exam BoardOCR MEI
ModuleFP1 (Further Pure Mathematics 1)
Year2006
SessionJune
Marks13
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSequences and series, recurrence and convergence
TypeFactorial or product method of differences
DifficultyStandard +0.3 This is a standard FP1 summation question testing method of differences and verification using standard formulae. Part (i) is straightforward algebra, part (ii) is a textbook application of differences (though worth 6 marks for showing telescoping), and part (iii) is routine substitution. While it requires multiple techniques, all are well-practiced FP1 methods with no novel insight needed, making it slightly easier than average overall.
Spec4.06b Method of differences: telescoping series

  1. Show that \(r(r+1)(r+2) - (r-1)r(r+1) \equiv 3r(r+1)\). [2]
  2. Hence use the method of differences to find an expression for \(\sum_{r=1}^{n} r(r+1)\). [6]
  3. Show that you can obtain the same expression for \(\sum_{r=1}^{n} r(r+1)\) using the standard formulae for \(\sum_{r=1}^{n} r\) and \(\sum_{r=1}^{n} r^2\). [5]

\begin{enumerate}[label=(\roman*)]
\item Show that $r(r+1)(r+2) - (r-1)r(r+1) \equiv 3r(r+1)$. [2]

\item Hence use the method of differences to find an expression for $\sum_{r=1}^{n} r(r+1)$. [6]

\item Show that you can obtain the same expression for $\sum_{r=1}^{n} r(r+1)$ using the standard formulae for $\sum_{r=1}^{n} r$ and $\sum_{r=1}^{n} r^2$. [5]
\end{enumerate}

\hfill \mbox{\textit{OCR MEI FP1 2006 Q9 [13]}}