OCR FP1 2010 June — Question 10 11 marks

Exam BoardOCR
ModuleFP1 (Further Pure Mathematics 1)
Year2010
SessionJune
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComplex Numbers Arithmetic
TypeSquare roots with follow-up application
DifficultyStandard +0.8 This FP1 question requires solving z² = 3+4i algebraically (equating real/imaginary parts), then using substitution u = w³ to solve a quadratic, followed by finding cube roots. While methodical, it demands careful algebraic manipulation across multiple steps, understanding of complex number properties, and argument constraints—significantly harder than typical A-level pure maths but standard for Further Maths.
Spec4.02h Square roots: of complex numbers4.02i Quadratic equations: with complex roots4.02j Cubic/quartic equations: conjugate pairs and factor theorem

The complex number \(z\), where \(0 < \arg z < \frac{1}{2}\pi\), is such that \(z^2 = 3 + 4\text{i}\).
  1. Use an algebraic method to find \(z\). [5]
  2. Show that \(z^3 = 2 + 11\text{i}\). [1]
The complex number \(w\) is the root of the equation $$w^6 - 4w^3 + 125 = 0$$ for which \(-\frac{1}{2}\pi < \arg w < 0\).
  1. Find \(w\). [5]

(i)
AnswerMarks
M1Attempt to equate real and imaginary parts
A1Obtain both results
M1Eliminate to obtain quadratic in \(x^2\) or \(y^2\)
M1Solve to obtain \(x\) or \(y\) value
A1 5Obtain correct answer as a complex no.
\(x^2 - y^2 = 3\) \(xy = 2\)
\(z = 2 + i\)
(ii)
AnswerMarks
B1 1Obtain given answer correctly
(iii)
AnswerMarks
M1Attempt to solve quadratic equation
A1Obtain correct answers
M1Choose negative sign
M1Relate required value to conjugate of (i)
A1 5Obtain correct answer
\(w^3 = 2 \pm 11i\)
\(w = 2 - i\)
## (i)
| M1 | Attempt to equate real and imaginary parts
| A1 | Obtain both results
| M1 | Eliminate to obtain quadratic in $x^2$ or $y^2$
| M1 | Solve to obtain $x$ or $y$ value
| A1 5 | Obtain correct answer as a complex no.

$x^2 - y^2 = 3$ $xy = 2$

$z = 2 + i$

## (ii)
| B1 1 | Obtain given answer correctly

## (iii)
| M1 | Attempt to solve quadratic equation
| A1 | Obtain correct answers
| M1 | Choose negative sign
| M1 | Relate required value to conjugate of (i)
| A1 5 | Obtain correct answer

$w^3 = 2 \pm 11i$

$w = 2 - i$
The complex number $z$, where $0 < \arg z < \frac{1}{2}\pi$, is such that $z^2 = 3 + 4\text{i}$.

\begin{enumerate}[label=(\roman*)]
\item Use an algebraic method to find $z$. [5]
\item Show that $z^3 = 2 + 11\text{i}$. [1]
\end{enumerate}

The complex number $w$ is the root of the equation
$$w^6 - 4w^3 + 125 = 0$$
for which $-\frac{1}{2}\pi < \arg w < 0$.

\begin{enumerate}[label=(\roman*)]
\setcounter{enumii}{2}
\item Find $w$. [5]
\end{enumerate}

\hfill \mbox{\textit{OCR FP1 2010 Q10 [11]}}