OCR FP1 2010 June — Question 8 9 marks

Exam BoardOCR
ModuleFP1 (Further Pure Mathematics 1)
Year2010
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSequences and series, recurrence and convergence
TypeSurd rationalization method of differences
DifficultyStandard +0.3 This is a standard FP1 telescoping series question with routine algebraic manipulation. Part (i) requires straightforward rationalisation of the denominator (a technique students know well). Part (ii) is a textbook telescoping sum where most terms cancel, leaving only boundary terms. Part (iii) is immediate once part (ii) is done. While it's Further Maths content, this is a very standard exercise type with no novel insight required—slightly easier than average overall.
Spec4.06b Method of differences: telescoping series

  1. Show that \(\frac{1}{\sqrt{r + 2} + \sqrt{r}} = \frac{\sqrt{r + 2} - \sqrt{r}}{2}\). [2]
  2. Hence find an expression, in terms of \(n\), for $$\sum_{r=1}^{n} \frac{1}{\sqrt{r + 2} + \sqrt{r}}.$$ [6]
  3. State, giving a brief reason, whether the series \(\sum_{r=1}^{\infty} \frac{1}{\sqrt{r + 2} + \sqrt{r}}\) converges. [1]

(i)
AnswerMarks
M1Attempt to rationalise denominator or cross multiply
A1 2Obtain given answer correctly
(ii)
AnswerMarks
M1Express terms as differences using (i)
M1Attempt this for at least 1st three terms
A11st three terms all correct
A1Last two terms all correct
M1Show pairs cancelling
A1 6Obtain correct answer, in terms of \(n\)
\(\frac{1}{2}(\sqrt{n+2} + \sqrt{n+1} - \sqrt{2} - 1)\)
(iii)
AnswerMarks
B1 1Sensible statement for divergence
## (i)
| M1 | Attempt to rationalise denominator or cross multiply
| A1 2 | Obtain given answer correctly

## (ii)
| M1 | Express terms as differences using (i)
| M1 | Attempt this for at least 1st three terms
| A1 | 1st three terms all correct
| A1 | Last two terms all correct
| M1 | Show pairs cancelling
| A1 6 | Obtain correct answer, in terms of $n$

$\frac{1}{2}(\sqrt{n+2} + \sqrt{n+1} - \sqrt{2} - 1)$

## (iii)
| B1 1 | Sensible statement for divergence

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\begin{enumerate}[label=(\roman*)]
\item Show that $\frac{1}{\sqrt{r + 2} + \sqrt{r}} = \frac{\sqrt{r + 2} - \sqrt{r}}{2}$. [2]
\item Hence find an expression, in terms of $n$, for
$$\sum_{r=1}^{n} \frac{1}{\sqrt{r + 2} + \sqrt{r}}.$$ [6]
\item State, giving a brief reason, whether the series $\sum_{r=1}^{\infty} \frac{1}{\sqrt{r + 2} + \sqrt{r}}$ converges. [1]
\end{enumerate}

\hfill \mbox{\textit{OCR FP1 2010 Q8 [9]}}