OCR MEI C4 — Question 2 8 marks

Exam BoardOCR MEI
ModuleC4 (Core Mathematics 4)
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicAddition & Double Angle Formulae
TypeIntegrate using double angle
DifficultyStandard +0.3 This is a standard C4 harmonic form question with routine integration. Part (i) is textbook R-cos(θ-α) manipulation yielding R=2, α=π/3. Part (ii) combines the standard derivative sec²θ with substitution u=tan θ, but the connection is straightforward once the harmonic form is recognized. The integration requires seeing that 1/(2cos(θ-π/3))² becomes ¼sec²(θ-π/3), making it slightly above average difficulty due to the multi-step nature, but all techniques are standard C4 material with no novel insight required.
Spec1.05j Trigonometric identities: tan=sin/cos and sin^2+cos^2=11.05n Harmonic form: a sin(x)+b cos(x) = R sin(x+alpha) etc1.08c Integrate e^(kx), 1/x, sin(kx), cos(kx)

  1. Express \(\cos \theta + \sqrt{3} \sin \theta\) in the form \(R \cos(\theta - \alpha)\), where \(R > 0\) and \(\alpha\) is acute, expressing \(\alpha\) in terms of \(\pi\). [4]
  2. Write down the derivative of \(\tan \theta\). Hence show that \(\int_0^{\frac{\pi}{6}} \frac{1}{(\cos \theta + \sqrt{3} \sin \theta)^2} d\theta = \frac{\sqrt{3}}{4}\). [4]

\begin{enumerate}[label=(\roman*)]
\item Express $\cos \theta + \sqrt{3} \sin \theta$ in the form $R \cos(\theta - \alpha)$, where $R > 0$ and $\alpha$ is acute, expressing $\alpha$ in terms of $\pi$. [4]

\item Write down the derivative of $\tan \theta$.

Hence show that $\int_0^{\frac{\pi}{6}} \frac{1}{(\cos \theta + \sqrt{3} \sin \theta)^2} d\theta = \frac{\sqrt{3}}{4}$. [4]
\end{enumerate}

\hfill \mbox{\textit{OCR MEI C4  Q2 [8]}}