The growth of a tree is modelled by the differential equation
$$10\frac{dh}{dt} = 20 - h$$
where \(h\) is its height in metres and the time \(t\) is in years. It is assumed that the tree is grown from seed, so that \(h = 0\) when \(t = 0\).
- Write down the value of \(h\) for which \(\frac{dh}{dt} = 0\), and interpret this in terms of the growth of the tree. [1]
- Verify that \(h = 20(1 - e^{-0.1t})\) satisfies this differential equation and its initial condition. [5]
The alternative differential equation
$$200\frac{dh}{dt} = 400 - h^2$$
is proposed to model the growth of the tree. As before, \(h = 0\) when \(t = 0\).
- Using partial fractions, show by integration that the solution to the alternative differential equation is
$$h = \frac{20(1 - e^{-0.2t})}{1 + e^{-0.2t}}$$ [9]
- What does this solution indicate about the long-term height of the tree? [1]
- After a year, the tree has grown to a height of 2m. Which model fits this information better? [3]