CAIE P1 2010 June — Question 5 7 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2010
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicTrigonometric equations in context
TypeExpress in terms of one trig function
DifficultyModerate -0.3 This is a straightforward multi-part question testing standard trigonometric identities and equation solving. Part (i) requires using sin²x + cos²x = 1 to rewrite the expression (routine manipulation), part (ii) involves finding range from the rewritten form (direct observation), and part (iii) is a basic quadratic-type equation in cos²x. All techniques are standard P1 material with no novel insight required, making it slightly easier than average.
Spec1.05j Trigonometric identities: tan=sin/cos and sin^2+cos^2=1

5 The function f is such that \(\mathrm { f } ( x ) = 2 \sin ^ { 2 } x - 3 \cos ^ { 2 } x\) for \(0 \leqslant x \leqslant \pi\).
  1. Express \(\mathrm { f } ( x )\) in the form \(a + b \cos ^ { 2 } x\), stating the values of \(a\) and \(b\).
  2. State the greatest and least values of \(\mathrm { f } ( x )\).
  3. Solve the equation \(\mathrm { f } ( x ) + 1 = 0\).

Question 5:
\(x \mapsto 2\sin^2 x - 3\cos^2 x\)
Part (i):
AnswerMarks Guidance
\(2(1 - \cos^2 x) - 3\cos^2 x\)M1 Uses \(s^2 + c^2 = 1\)
\(\rightarrow 2 - 5\cos^2 x\ (a=2,\ b=-5)\)A1 [2] co
Part (ii):
AnswerMarks
Values are \(-3\) and \(2\)B1\(\sqrt{}\) B1\(\sqrt{}\) [2]
Part (iii):
\(2 - 5\cos^2 x = -1 \rightarrow \cos^2 x = 0.6\)
AnswerMarks Guidance
\(x = 0.685,\ 2.46\) (accept 0.684)B1\(\sqrt{}\), B1 B1\(\sqrt{}\) [3] co \(\sqrt{}\) for \(\pi -\) (first answer). SC B1 for both 39.2 and 140.8
## Question 5:

$x \mapsto 2\sin^2 x - 3\cos^2 x$

**Part (i):**
$2(1 - \cos^2 x) - 3\cos^2 x$ | M1 | Uses $s^2 + c^2 = 1$

$\rightarrow 2 - 5\cos^2 x\ (a=2,\ b=-5)$ | A1 [2] | co

**Part (ii):**
Values are $-3$ and $2$ | B1$\sqrt{}$ B1$\sqrt{}$ [2] |

**Part (iii):**
$2 - 5\cos^2 x = -1 \rightarrow \cos^2 x = 0.6$

$x = 0.685,\ 2.46$ (accept 0.684) | B1$\sqrt{}$, B1 B1$\sqrt{}$ [3] | co $\sqrt{}$ for $\pi -$ (first answer). SC B1 for both 39.2 and 140.8

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5 The function f is such that $\mathrm { f } ( x ) = 2 \sin ^ { 2 } x - 3 \cos ^ { 2 } x$ for $0 \leqslant x \leqslant \pi$.\\
(i) Express $\mathrm { f } ( x )$ in the form $a + b \cos ^ { 2 } x$, stating the values of $a$ and $b$.\\
(ii) State the greatest and least values of $\mathrm { f } ( x )$.\\
(iii) Solve the equation $\mathrm { f } ( x ) + 1 = 0$.

\hfill \mbox{\textit{CAIE P1 2010 Q5 [7]}}