CAIE P1 2010 June — Question 2 5 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2010
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicBinomial Theorem (positive integer n)
TypeProduct with reciprocal term binomial
DifficultyModerate -0.3 This is a straightforward binomial expansion question requiring standard application of the binomial theorem with a two-term expression containing x and 1/x. Part (i) is routine calculation, and part (ii) requires identifying which terms from the product yield x, which is a common exam technique but requires minimal problem-solving beyond pattern recognition.
Spec1.04a Binomial expansion: (a+b)^n for positive integer n

2
  1. Find the first 3 terms in the expansion of \(\left( 2 x - \frac { 3 } { x } \right) ^ { 5 }\) in descending powers of \(x\).
  2. Hence find the coefficient of \(x\) in the expansion of \(\left( 1 + \frac { 2 } { x ^ { 2 } } \right) \left( 2 x - \frac { 3 } { x } \right) ^ { 5 }\).

Question 2:
Part (i):
AnswerMarks Guidance
\(32x^5 - 240x^3 + 720x\)\(3 \times\) B1 [3] co. SC B2 for other 3 terms (i.e. ascending)
Part (ii):
\(\left(1 + \frac{2}{x^2}\right)(32x^5 - 240x^3 + 720x)\)
AnswerMarks Guidance
Coeff of \(x\): \((1 \times 720) + (2 \times -240) \rightarrow 240\)M1, A1\(\sqrt{}\) [2] Looks at exactly 2 terms. co from his answer to (i)
## Question 2:

**Part (i):**
$32x^5 - 240x^3 + 720x$ | $3 \times$ B1 [3] | co. SC B2 for other 3 terms (i.e. ascending)

**Part (ii):**
$\left(1 + \frac{2}{x^2}\right)(32x^5 - 240x^3 + 720x)$

Coeff of $x$: $(1 \times 720) + (2 \times -240) \rightarrow 240$ | M1, A1$\sqrt{}$ [2] | Looks at exactly 2 terms. co from his answer to (i)

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2 (i) Find the first 3 terms in the expansion of $\left( 2 x - \frac { 3 } { x } \right) ^ { 5 }$ in descending powers of $x$.\\
(ii) Hence find the coefficient of $x$ in the expansion of $\left( 1 + \frac { 2 } { x ^ { 2 } } \right) \left( 2 x - \frac { 3 } { x } \right) ^ { 5 }$.

\hfill \mbox{\textit{CAIE P1 2010 Q2 [5]}}