CAIE P1 2010 June — Question 6 7 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2010
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicDifferential equations
TypeFirst-order integration
DifficultyModerate -0.8 This is a straightforward first-order differential equation requiring direct integration of a simple power function, followed by using a boundary condition to find the constant. Part (ii) involves basic stationary point analysis (setting derivative to zero and using second derivative test). Both parts are routine AS-level techniques with no problem-solving insight required, making this easier than average.
Spec1.07i Differentiate x^n: for rational n and sums1.07n Stationary points: find maxima, minima using derivatives1.08b Integrate x^n: where n != -1 and sums

6 A curve is such that \(\frac { \mathrm { d } y } { \mathrm {~d} x } = 3 x ^ { \frac { 1 } { 2 } } - 6\) and the point \(( 9,2 )\) lies on the curve.
  1. Find the equation of the curve.
  2. Find the \(x\)-coordinate of the stationary point on the curve and determine the nature of the stationary point.

Question 6:
\(\frac{dy}{dx} = 3\sqrt{x} - 6\quad (9, 2)\)
Part (i):
AnswerMarks Guidance
\(y = \frac{3x^{\frac{3}{2}}}{\frac{3}{2}} - 6x\ (+c)\)B2,1 Loses 1 for each error – ignore \(+c\)
\((9,\ 2):\ 2 = 54 - 54 + c \rightarrow c = 2\)M1 A1 [4] Uses \((9, 2)\) with integration to find \(c\). co
Part (ii):
AnswerMarks Guidance
\(\frac{dy}{dx} = 0 \rightarrow x = 4\)B1 Ignore any \(y\)-value
\(\frac{d^2y}{dx^2} = \frac{3x^{-\frac{1}{2}}}{2}\), \(\rightarrow\) +ve (or \(\frac{3}{4}\)) MinimumM1 A1 [3] Any valid method. co
## Question 6:

$\frac{dy}{dx} = 3\sqrt{x} - 6\quad (9, 2)$

**Part (i):**
$y = \frac{3x^{\frac{3}{2}}}{\frac{3}{2}} - 6x\ (+c)$ | B2,1 | Loses 1 for each error – ignore $+c$

$(9,\ 2):\ 2 = 54 - 54 + c \rightarrow c = 2$ | M1 A1 [4] | Uses $(9, 2)$ with integration to find $c$. co

**Part (ii):**
$\frac{dy}{dx} = 0 \rightarrow x = 4$ | B1 | Ignore any $y$-value

$\frac{d^2y}{dx^2} = \frac{3x^{-\frac{1}{2}}}{2}$, $\rightarrow$ +ve (or $\frac{3}{4}$) Minimum | M1 A1 [3] | Any valid method. co

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6 A curve is such that $\frac { \mathrm { d } y } { \mathrm {~d} x } = 3 x ^ { \frac { 1 } { 2 } } - 6$ and the point $( 9,2 )$ lies on the curve.\\
(i) Find the equation of the curve.\\
(ii) Find the $x$-coordinate of the stationary point on the curve and determine the nature of the stationary point.

\hfill \mbox{\textit{CAIE P1 2010 Q6 [7]}}