| Exam Board | CAIE |
|---|---|
| Module | FP2 (Further Pure Mathematics 2) |
| Year | 2019 |
| Session | June |
| Marks | 8 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | T-tests (unknown variance) |
| Type | Paired sample t-test |
| Difficulty | Standard +0.3 This is a standard paired t-test with clear structure: calculate differences, find mean and standard deviation, apply the t-test formula, and compare to critical value. While it requires multiple computational steps and understanding of hypothesis testing, it follows a routine procedure taught in statistics courses with no novel insight required. The 10% significance level and one-tailed nature are clearly stated, making it slightly easier than average A-level questions. |
| Spec | 5.05c Hypothesis test: normal distribution for population mean |
| Runner | \(A\) | \(B\) | \(C\) | \(D\) | \(E\) | \(F\) |
| Time at beginning of camp | 3.82 | 3.62 | 3.55 | 3.71 | 3.75 | 3.92 |
| Time at end of camp | 3.72 | 3.55 | 3.52 | 3.68 | 3.54 | 3.73 |
| Answer | Marks | Guidance |
|---|---|---|
| 8 | H : µ – µ = 0⋅05, H : µ – µ > 0⋅05 (AEF) | |
| 0 b e 1 b e | B1 | State both hypotheses (B0 for x … ) |
| Answer | Marks | Guidance |
|---|---|---|
| i | M1 | Consider differences d from e.g. x – y |
| Answer | Marks | Guidance |
|---|---|---|
| d = 0⋅63 / 6 = 0⋅105 (or 6⋅3 sec) | B1 | Find sample mean |
| Answer | Marks | Guidance |
|---|---|---|
| [ = 123/20 000 or 0⋅00615 or 0⋅07842 ] (or 22⋅14) | M1 | Estimate population variance |
| Answer | Marks | Guidance |
|---|---|---|
| 5, 0.9 | B1 | State or use correct tabular t-value |
| t = (d – 0⋅05) / (s/√6) = 1⋅72 | M1 A1 | Find value of t |
| Answer | Marks | Guidance |
|---|---|---|
| or times improve by more than 0⋅05 min (AEF) | B1 | FT on both t-values |
| Answer | Marks | Guidance |
|---|---|---|
| Question | Answer | Marks |
Question 8:
8 | H : µ – µ = 0⋅05, H : µ – µ > 0⋅05 (AEF)
0 b e 1 b e | B1 | State both hypotheses (B0 for x … )
d: 0⋅10 0⋅07 0⋅03 0⋅03 0⋅21 0⋅19 (or in sec)
i | M1 | Consider differences d from e.g. x – y
i b e
d = 0⋅63 / 6 = 0⋅105 (or 6⋅3 sec) | B1 | Find sample mean
s2 = (0⋅0969 – 0⋅632/6) / 5
[ = 123/20 000 or 0⋅00615 or 0⋅07842 ] (or 22⋅14) | M1 | Estimate population variance
(allow biased here: [41/8000 or 0⋅005125 or 0⋅07162 ])
t = 1⋅476 (to 3 sf)
5, 0.9 | B1 | State or use correct tabular t-value
t = (d – 0⋅05) / (s/√6) = 1⋅72 | M1 A1 | Find value of t
(or compare d −0⋅05 = 0⋅055 with (t )s/√6 = 0⋅0473)
5, 0.9
[Reject H :] Evidence for organiser’s belief
0
or times improve by more than 0⋅05 min (AEF) | B1 | FT on both t-values
Consistent conclusion
SC Wrong type of hypothesis test can earn only
B1 for hypotheses
B1FT for conclusion (max 2/8)
8
Question | Answer | Marks | GuidanceA large number of runners are attending a summer training camp. A random sample of 6 runners is chosen and their times to run 1500 m at the beginning of the camp and at the end of the camp are recorded. Their times, in minutes, are shown in the following table.
\begin{tabular}{|l|c|c|c|c|c|c|}
\hline
Runner & $A$ & $B$ & $C$ & $D$ & $E$ & $F$ \\
\hline
Time at beginning of camp & 3.82 & 3.62 & 3.55 & 3.71 & 3.75 & 3.92 \\
\hline
Time at end of camp & 3.72 & 3.55 & 3.52 & 3.68 & 3.54 & 3.73 \\
\hline
\end{tabular}
The organiser of the training camp claims that a runner's time will improve by more than 0.05 minutes between the beginning and end of the camp. Assuming that differences in time over the two runs are normally distributed, test at the 10% significance level whether the organiser's claim is justified. [8]
\hfill \mbox{\textit{CAIE FP2 2019 Q8 [8]}}