CAIE FP2 2019 June — Question 11 24 marks

Exam BoardCAIE
ModuleFP2 (Further Pure Mathematics 2)
Year2019
SessionJune
Marks24
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCircular Motion 2
TypeCollision/impulse during circular motion
DifficultyChallenging +1.8 This is a challenging Further Maths mechanics problem requiring multiple stages: energy conservation to find speed at lowest point, collision mechanics with conservation of momentum and energy considerations, then circular motion analysis to find the loss-of-contact angle. The multi-step nature, involving three distinct mechanical principles applied sequentially with careful bookkeeping of masses and speeds, places it well above average difficulty but not at the extreme end for FM questions.
Spec6.02i Conservation of energy: mechanical energy principle6.03b Conservation of momentum: 1D two particles6.03k Newton's experimental law: direct impact6.05f Vertical circle: motion including free fall

Answer only one of the following two alternatives. **EITHER** A particle \(P\), of mass \(m\), is able to move in a vertical circle on the smooth inner surface of a sphere with centre \(O\) and radius \(a\). Points \(A\) and \(B\) are on the inner surface of the sphere and \(AOB\) is a horizontal diameter. Initially, \(P\) is projected vertically downwards with speed \(\sqrt{\left(\frac{21}{2}ag\right)}\) from \(A\) and begins to move in a vertical circle. At the lowest point of its path, vertically below \(O\), the particle \(P\) collides with a stationary particle \(Q\), of mass \(4m\), and rebounds. The speed acquired by \(Q\), as a result of the collision, is just sufficient for it to reach the point \(B\).
  1. Find the speed of \(P\) and the speed of \(Q\) immediately after their collision. [7] In its subsequent motion, \(P\) loses contact with the inner surface of the sphere at the point \(D\), where the angle between \(OD\) and the upward vertical through \(O\) is \(\theta\).
  2. Find \(\cos \theta\). [5] **OR** A farmer grows two different types of cherries, Type A and Type B. He assumes that the masses of each type are normally distributed. He chooses a random sample of 8 cherries of Type A. He finds that the sample mean mass is 15.1 g and that a 95% confidence interval for the population mean mass, \(\mu\) g, is \(13.5 \leqslant \mu \leqslant 16.7\).
  3. Find an unbiased estimate for the population variance of the masses of cherries of Type A. [3] The farmer now chooses a random sample of 6 cherries of Type B and records their masses as follows. $$12.2 \quad 13.3 \quad 16.4 \quad 14.0 \quad 13.9 \quad 15.4$$
  4. Test at the 5% significance level whether the mean mass of cherries of Type B is less than the mean mass of cherries of Type A. You should assume that the population variances for the two types of cherry are equal. [9]

Answer only one of the following two alternatives.

**EITHER**

A particle $P$, of mass $m$, is able to move in a vertical circle on the smooth inner surface of a sphere with centre $O$ and radius $a$. Points $A$ and $B$ are on the inner surface of the sphere and $AOB$ is a horizontal diameter. Initially, $P$ is projected vertically downwards with speed $\sqrt{\left(\frac{21}{2}ag\right)}$ from $A$ and begins to move in a vertical circle. At the lowest point of its path, vertically below $O$, the particle $P$ collides with a stationary particle $Q$, of mass $4m$, and rebounds. The speed acquired by $Q$, as a result of the collision, is just sufficient for it to reach the point $B$.

(i) Find the speed of $P$ and the speed of $Q$ immediately after their collision. [7]

In its subsequent motion, $P$ loses contact with the inner surface of the sphere at the point $D$, where the angle between $OD$ and the upward vertical through $O$ is $\theta$.

(ii) Find $\cos \theta$. [5]

**OR**

A farmer grows two different types of cherries, Type A and Type B. He assumes that the masses of each type are normally distributed. He chooses a random sample of 8 cherries of Type A. He finds that the sample mean mass is 15.1 g and that a 95% confidence interval for the population mean mass, $\mu$ g, is $13.5 \leqslant \mu \leqslant 16.7$.

(i) Find an unbiased estimate for the population variance of the masses of cherries of Type A. [3]

The farmer now chooses a random sample of 6 cherries of Type B and records their masses as follows.
$$12.2 \quad 13.3 \quad 16.4 \quad 14.0 \quad 13.9 \quad 15.4$$

(ii) Test at the 5% significance level whether the mean mass of cherries of Type B is less than the mean mass of cherries of Type A. You should assume that the population variances for the two types of cherry are equal. [9]

\hfill \mbox{\textit{CAIE FP2 2019 Q11 [24]}}