CAIE P3 2018 June — Question 10 8 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2018
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStandard trigonometric equations
TypeSketch and solve graphically
DifficultyModerate -0.3 This is a straightforward multi-part question on standard trigonometric equations. Part (i) uses the standard technique of rearranging to tan x = constant. Part (ii) is routine graph sketching of basic trig functions. Part (iii) requires reading off inequalities from the graphs, which is a standard skill. The question requires no novel insight and follows textbook methods throughout, making it slightly easier than average.
Spec1.05a Sine, cosine, tangent: definitions for all arguments1.05f Trigonometric function graphs: symmetries and periodicities1.05o Trigonometric equations: solve in given intervals

  1. Solve the equation \(2 \cos x + 3 \sin x = 0\), for \(0° \leqslant x \leqslant 360°\). [3]
  2. Sketch, on the same diagram, the graphs of \(y = 2 \cos x\) and \(y = -3 \sin x\) for \(0° \leqslant x \leqslant 360°\). [3]
  3. Use your answers to parts (i) and (ii) to find the set of values of \(x\) for \(0° \leqslant x \leqslant 360°\) for which \(2 \cos x + 3 \sin x > 0\). [2]

Question 10:

AnswerMarks Guidance
10(i)Equate at least two pairs of components and solve for s or for t M1
 3 s=−6  5
  t = −5 or   t =−11 or   t = −13
3 5
  
7≠−7
−5≠ −1 6 ≠ −8
 3 5 5
AnswerMarks
Obtain correct answer for s or t, e.g. s = – 6, t = – 11A1
Verify that all three equations are not satisfied and the lines fail
AnswerMarks
to intersectA1
State that the lines are not parallelB1
4

AnswerMarks
10(ii)EITHER: Use scalar product to obtain a relevant
equation in a, b and c, e.g. 2a + 3b – c = 0B1
Obtain a second equation, e.g. a + 2b +c = 0,
AnswerMarks
and solve for one ratio, e.g. a : bM1
Obtain a : b : c and state correct answer, e.g.
AnswerMarks
5i – 3j + k, or equivalentA1
OR: Attempt to calculate vector product of
AnswerMarks
relevant vectors, e.g. (2i + 3j – k)×(i + 2j + k)M1
Obtain two correct componentsA1
Obtain correct answer, e.g. 5i – 3j + kA1
3
AnswerMarks Guidance
QuestionAnswer Marks

AnswerMarks
10(iii)EITHER: State position vector or coordinates of the
mid-point of a line segment joining points on l
3 5
and m, e.g. i+j + k
AnswerMarks Guidance
2 2B1 OR: Use the result of (ii) to form equations of planes containing
l and m B1
Use the result of (ii) and the mid-point to
AnswerMarks Guidance
find dM1 Use average of distances to find equation of p. M1
Obtain answer 5x – 3y + z = 7, or equivalentA1 Obtain answer 5x – 3y + z = 7, or equivalent A1
OR: Using the result of part (ii), form an equation
in d by equating perpendicular distances to
AnswerMarks
the plane of a point on l and a point on mM1
14−d −d
State a correct equation, e.g. =
AnswerMarks
35 35A1
Solve for d and obtain answer 5x – 3y + z =
AnswerMarks
7, or equivalentA1
3
Question 10:
--- 10(i) ---
10(i) | Equate at least two pairs of components and solve for s or for t | M1 |  s= −4  s= −2
 3 s=−6  5
  t = −5 or   t =−11 or   t = −13
3 5
  
7≠−7
−5≠ −1 6 ≠ −8
 3 5 5
Obtain correct answer for s or t, e.g. s = – 6, t = – 11 | A1
Verify that all three equations are not satisfied and the lines fail
to intersect | A1
State that the lines are not parallel | B1
4
--- 10(ii) ---
10(ii) | EITHER: Use scalar product to obtain a relevant
equation in a, b and c, e.g. 2a + 3b – c = 0 | B1
Obtain a second equation, e.g. a + 2b +c = 0,
and solve for one ratio, e.g. a : b | M1
Obtain a : b : c and state correct answer, e.g.
5i – 3j + k, or equivalent | A1
OR: Attempt to calculate vector product of
relevant vectors, e.g. (2i + 3j – k)×(i + 2j + k) | M1
Obtain two correct components | A1
Obtain correct answer, e.g. 5i – 3j + k | A1
3
Question | Answer | Marks | Guidance
--- 10(iii) ---
10(iii) | EITHER: State position vector or coordinates of the
mid-point of a line segment joining points on l
3 5
and m, e.g. i+j + k
2 2 | B1 | OR: Use the result of (ii) to form equations of planes containing
l and m B1
Use the result of (ii) and the mid-point to
find d | M1 | Use average of distances to find equation of p. M1
Obtain answer 5x – 3y + z = 7, or equivalent | A1 | Obtain answer 5x – 3y + z = 7, or equivalent A1
OR: Using the result of part (ii), form an equation
in d by equating perpendicular distances to
the plane of a point on l and a point on m | M1
14−d −d
State a correct equation, e.g. =
35 35 | A1
Solve for d and obtain answer 5x – 3y + z =
7, or equivalent | A1
3
\begin{enumerate}[label=(\roman*)]
\item Solve the equation $2 \cos x + 3 \sin x = 0$, for $0° \leqslant x \leqslant 360°$. [3]

\item Sketch, on the same diagram, the graphs of $y = 2 \cos x$ and $y = -3 \sin x$ for $0° \leqslant x \leqslant 360°$. [3]

\item Use your answers to parts (i) and (ii) to find the set of values of $x$ for $0° \leqslant x \leqslant 360°$ for which $2 \cos x + 3 \sin x > 0$. [2]
\end{enumerate}

\hfill \mbox{\textit{CAIE P3 2018 Q10 [8]}}