CAIE P3 2018 June — Question 8 7 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2018
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStraight Lines & Coordinate Geometry
TypeCoordinates from geometric constraints
DifficultyStandard +0.3 This is a straightforward coordinate geometry problem requiring finding the midpoint, calculating the gradient of AB, using the perpendicular gradient property, and solving simultaneous equations. While it involves multiple steps (7 marks), each step uses standard A-level techniques with no novel insight required, making it slightly easier than average.
Spec1.03a Straight lines: equation forms y=mx+c, ax+by+c=01.03b Straight lines: parallel and perpendicular relationships

Points \(A\) and \(B\) have coordinates \((h, h)\) and \((4h + 6, 5h)\) respectively. The equation of the perpendicular bisector of \(AB\) is \(3x + 2y = k\). Find the values of the constants \(h\) and \(k\). [7]

Question 8:

AnswerMarks Guidance
8(i)Use correct product or quotient rule M1
dx 3
e 1 3 x − ( x+1 )1 e 1 3 x
or dy = 3
dx 2x
e3
AnswerMarks
Obtain complete correct derivative in any formA1
Equate derivative to zero and solve for xM1
Obtain answer x = 2 with no errors seenA1
4

AnswerMarks
8(ii)1 1
Integrate by parts and reach a ( x+1 ) e − 3 x +b∫e − 3 x dxM1*
1 1
AnswerMarks Guidance
Obtain −3 ( x+1 ) e − 3 x +3∫e − 3 x dx, or equivalentA1 −3xe −1 3 x + ∫3e −1 3 x dx−3e −1 3 x
1 1
Complete integration and obtain −3 ( x+1 ) e − 3 x −9e − 3 x , or
AnswerMarks
equivalentA1
Use correct limits x = – 1 and x = 0 in the correct order,
AnswerMarks
having integrated twiceM1(dep*)
1
AnswerMarks
Obtain answer 9e3 −12, or equivalentA1
5
AnswerMarks Guidance
QuestionAnswer Marks
Question 8:
--- 8(i) ---
8(i) | Use correct product or quotient rule | M1 | dy = 1 ( x+1 ) e −1 3 x +e −1 3 x
−
dx 3
e 1 3 x − ( x+1 )1 e 1 3 x
or dy = 3
dx 2x
e3
Obtain complete correct derivative in any form | A1
Equate derivative to zero and solve for x | M1
Obtain answer x = 2 with no errors seen | A1
4
--- 8(ii) ---
8(ii) | 1 1
Integrate by parts and reach a ( x+1 ) e − 3 x +b∫e − 3 x dx | M1*
1 1
Obtain −3 ( x+1 ) e − 3 x +3∫e − 3 x dx, or equivalent | A1 | −3xe −1 3 x + ∫3e −1 3 x dx−3e −1 3 x
1 1
Complete integration and obtain −3 ( x+1 ) e − 3 x −9e − 3 x , or
equivalent | A1
Use correct limits x = – 1 and x = 0 in the correct order,
having integrated twice | M1(dep*)
1
Obtain answer 9e3 −12, or equivalent | A1
5
Question | Answer | Marks | Guidance
Points $A$ and $B$ have coordinates $(h, h)$ and $(4h + 6, 5h)$ respectively. The equation of the perpendicular bisector of $AB$ is $3x + 2y = k$. Find the values of the constants $h$ and $k$. [7]

\hfill \mbox{\textit{CAIE P3 2018 Q8 [7]}}