CAIE P1 2024 November — Question 2 5 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2024
SessionNovember
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicArithmetic Sequences and Series
TypeFind n given sum condition
DifficultyModerate -0.8 Part (a) is direct application of the arithmetic series formula with given values. Part (b) requires setting up an equation S_{2k} = 10S_k and solving for k, which involves algebraic manipulation but follows a standard pattern for AS-level arithmetic progression questions. The question is straightforward with no conceptual challenges beyond formula application.
Spec1.04h Arithmetic sequences: nth term and sum formulae

The first term of an arithmetic progression is \(-20\) and the common difference is \(5\).
  1. Find the sum of the first 20 terms of the progression. [2]
It is given that the sum of the first \(2k\) terms is 10 times the sum of the first \(k\) terms.
  1. Find the value of \(k\). [3]

Question 2:

AnswerMarks
2(a)20 20
( 2−20+(20−1)5 ) (−20+75)
or
AnswerMarks Guidance
2 2M1 Correct use of either S formula with a = —20 and d = 5.
20
AnswerMarks
550A1
2

AnswerMarks
2(b)2k k
( −40+(2k−1)5 ) or ( −40+(k−1)5 )
AnswerMarks Guidance
2 2M1* Correct use of S formula with a=−20, d=5 and either k or
n
2k.
n
(a+l)
This mark can be awarded for clear use of when
2
correct values of a and d are used.
−40k+10k2 −5k =−200k+25k2 −25k  1 5k2 −180k =0
AnswerMarks Guidance
 DM1 Equating their S to 10 × their S and reaching a 2-term
2k k
quadratic or 2 term linear equation if k has been cancelled.
Condone errors in simplification.
AnswerMarks Guidance
k=12A1 Condone extra solution k =0.
3
AnswerMarks Guidance
QuestionAnswer Marks
Question 2:
--- 2(a) ---
2(a) | 20 20
( 2−20+(20−1)5 ) (−20+75)
or
2 2 | M1 | Correct use of either S formula with a = —20 and d = 5.
20
550 | A1
2
--- 2(b) ---
2(b) | 2k k
( −40+(2k−1)5 ) or ( −40+(k−1)5 )
2 2 | M1* | Correct use of S formula with a=−20, d=5 and either k or
n
2k.
n
(a+l)
This mark can be awarded for clear use of when
2
correct values of a and d are used.
−40k+10k2 −5k =−200k+25k2 −25k  1 5k2 −180k =0
  | DM1 | Equating their S to 10 × their S and reaching a 2-term
2k k
quadratic or 2 term linear equation if k has been cancelled.
Condone errors in simplification.
k=12 | A1 | Condone extra solution k =0.
3
Question | Answer | Marks | Guidance
The first term of an arithmetic progression is $-20$ and the common difference is $5$.

\begin{enumerate}[label=(\alph*)]
\item Find the sum of the first 20 terms of the progression. [2]
\end{enumerate}

It is given that the sum of the first $2k$ terms is 10 times the sum of the first $k$ terms.

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{1}
\item Find the value of $k$. [3]
\end{enumerate}

\hfill \mbox{\textit{CAIE P1 2024 Q2 [5]}}