A function f with domain \(x > 0\) is such that \(\mathrm{f}'(x) = 8(2x - 3)^{\frac{1}{3}} - 10x^{\frac{3}{5}}\). It is given that the curve with equation \(y = \mathrm{f}(x)\) passes through the point \((1, 0)\).
- Find the equation of the normal to the curve at the point \((1, 0)\). [3]
- Find f\((x)\). [4]
It is given that the equation \(\mathrm{f}'(x) = 0\) can be expressed in the form
$$125x^2 - 128x + 192 = 0.$$
- Determine, making your reasoning clear, whether f is an increasing function, a decreasing function or neither. [3]