Pre-U Pre-U 9794/1 Specimen — Question 7 11 marks

Exam BoardPre-U
ModulePre-U 9794/1 (Pre-U Mathematics Paper 1)
SessionSpecimen
Marks11
TopicVectors 3D & Lines
TypeLine intersection verification
DifficultyStandard +0.3 This is a standard 3D vectors question covering routine techniques: checking line intersection by equating components (straightforward algebra), finding angle between direction vectors using dot product formula, using perpendicularity conditions with cross products, and applying the standard volume formula. All parts follow textbook methods with no novel insight required, though it does require careful algebraic manipulation across multiple parts.
Spec1.10b Vectors in 3D: i,j,k notation1.10c Magnitude and direction: of vectors1.10g Problem solving with vectors: in geometry4.04g Vector product: a x b perpendicular vector

7 With respect to the origin \(O\), the points \(A\) and \(B\) have position vectors \(\mathbf { a }\) and \(\mathbf { b }\) respectively, where \(\mathbf { a } = 2 \mathbf { i } - 3 \mathbf { j } + 6 \mathbf { k }\) and \(\mathbf { b } = - \mathbf { i } - \mathbf { j } + 2 \mathbf { k }\). The lines \(L _ { 1 }\) and \(L _ { 2 }\) have the vector equations $$\mathbf { r } = \mathbf { a } + \lambda \mathbf { b } , \quad \mathbf { r } = 2 \mathbf { b } + \mu \mathbf { a }$$ respectively.
  1. Determine whether or not \(L _ { 1 }\) and \(L _ { 2 }\) intersect.
  2. Find the acute angle between the directions of \(L _ { 1 }\) and \(L _ { 2 }\). The point \(C\) has position vector \(\mathbf { c } = p \mathbf { i } + \mathbf { j } + r \mathbf { k }\).
  3. Given that \(O C\) is perpendicular to the triangle \(O A B\), determine \(p\) and \(r\).
  4. Determine the volume of the tetrahedron \(O A B C\).

(i) The lines intersect [B1] 1 mark
AnswerMarks Guidance
(ii) Use of \(\cos\theta = \frac{\mathbf{a} \cdot \mathbf{b}}{\mathbf{a}
\(= \frac{2\times(-1) + (-3)\times(-1) + 6\times2}{\sqrt{2^2+(-3)^2+6^2} \times \sqrt{(-1)^2+(-1)^2+2^2}}\) [A1]
\(\theta = 0.710\) or \(40.7°\) [A1] 3 marks
(iii) Use of \(\mathbf{c} \cdot \mathbf{v} = 0\) for two vectors [M1]
Obtain two equations: \(2p - 3 + 6r = 0\) [A1]
\(-p - 1 + 2r = 0\) [A1]
Solve and obtain \(p = 0\), \(r = \frac{1}{2}\) [A1] 4 marks
(iv) Use of volume \(= \frac{1}{3}\)(area of triangle \(OAB\))(height \(OC\)) [M1]
Use of area of triangle \(OAB = \frac{1}{2}OA \times OB \sin\theta\) [M1]
Obtain 2.08 [A1] 3 marks
(i) The lines intersect [B1] **1 mark**

(ii) Use of $\cos\theta = \frac{\mathbf{a} \cdot \mathbf{b}}{|\mathbf{a}||\mathbf{b}|}$ [M1]
$= \frac{2\times(-1) + (-3)\times(-1) + 6\times2}{\sqrt{2^2+(-3)^2+6^2} \times \sqrt{(-1)^2+(-1)^2+2^2}}$ [A1]
$\theta = 0.710$ or $40.7°$ [A1] **3 marks**

(iii) Use of $\mathbf{c} \cdot \mathbf{v} = 0$ for two vectors [M1]
Obtain two equations: $2p - 3 + 6r = 0$ [A1]
$-p - 1 + 2r = 0$ [A1]
Solve and obtain $p = 0$, $r = \frac{1}{2}$ [A1] **4 marks**

(iv) Use of volume $= \frac{1}{3}$(area of triangle $OAB$)(height $OC$) [M1]
Use of area of triangle $OAB = \frac{1}{2}OA \times OB \sin\theta$ [M1]
Obtain 2.08 [A1] **3 marks**
7 With respect to the origin $O$, the points $A$ and $B$ have position vectors $\mathbf { a }$ and $\mathbf { b }$ respectively, where $\mathbf { a } = 2 \mathbf { i } - 3 \mathbf { j } + 6 \mathbf { k }$ and $\mathbf { b } = - \mathbf { i } - \mathbf { j } + 2 \mathbf { k }$.

The lines $L _ { 1 }$ and $L _ { 2 }$ have the vector equations

$$\mathbf { r } = \mathbf { a } + \lambda \mathbf { b } , \quad \mathbf { r } = 2 \mathbf { b } + \mu \mathbf { a }$$

respectively.\\
(i) Determine whether or not $L _ { 1 }$ and $L _ { 2 }$ intersect.\\
(ii) Find the acute angle between the directions of $L _ { 1 }$ and $L _ { 2 }$.

The point $C$ has position vector $\mathbf { c } = p \mathbf { i } + \mathbf { j } + r \mathbf { k }$.\\
(iii) Given that $O C$ is perpendicular to the triangle $O A B$, determine $p$ and $r$.\\
(iv) Determine the volume of the tetrahedron $O A B C$.

\hfill \mbox{\textit{Pre-U Pre-U 9794/1  Q7 [11]}}