Pre-U Pre-U 9794/1 Specimen — Question 4 4 marks

Exam BoardPre-U
ModulePre-U 9794/1 (Pre-U Mathematics Paper 1)
SessionSpecimen
Marks4
TopicTangents, normals and gradients
TypeNormal meets curve/axis — further geometry
DifficultyStandard +0.8 This question requires finding tangent/normal equations and their intersection point. While the calculus is straightforward (differentiating sin x), part (iii) demands solving simultaneous equations with exact trigonometric values, requiring careful algebraic manipulation. The multi-step nature and need for exact answers elevate this above routine differentiation exercises, but it remains a standard A-level technique without requiring novel insight.
Spec1.05f Trigonometric function graphs: symmetries and periodicities1.05o Trigonometric equations: solve in given intervals1.07m Tangents and normals: gradient and equations

4
  1. Sketch the graph of \(y = \sqrt { 2 } \sin x\) for \(0 \leqslant x \leqslant 2 \pi\). The points \(P\) and \(Q\) on the graph have \(x\)-coordinates \(\frac { 1 } { 4 } \pi\) and \(\frac { 3 } { 4 } \pi\), respectively.
  2. Determine the equation of the tangent to the curve at \(P\). The normals to the curve at \(P\) and \(Q\) intersect at the point \(R\).
  3. Determine the exact coordinates of \(R\).

(i) Graph of correct sinusoidal shape [B1]
Correct \(x\)-intercepts and range indicated [B1] 2 marks
(ii) Gradient of tangent at \(P\left(\frac{1}{4}\pi, 1\right)\) is \(\sqrt{2}\cos(\frac{1}{4}\pi) = 1\) [M1]
Equation of tangent at \(P\) is \(y - 1 = x - \frac{1}{4}\pi\) [A1] 2 marks
(iii) Equation of normal at \(P\) is \(y - 1 = -(x - \frac{1}{4}\pi)\) [M1A1]
\(R\) has coordinates \(\left(\frac{1}{2}\pi, 1 - \frac{1}{4}\pi\right)\) [A1A1] 4 marks
(i) Graph of correct sinusoidal shape [B1]
Correct $x$-intercepts and range indicated [B1] **2 marks**

(ii) Gradient of tangent at $P\left(\frac{1}{4}\pi, 1\right)$ is $\sqrt{2}\cos(\frac{1}{4}\pi) = 1$ [M1]
Equation of tangent at $P$ is $y - 1 = x - \frac{1}{4}\pi$ [A1] **2 marks**

(iii) Equation of normal at $P$ is $y - 1 = -(x - \frac{1}{4}\pi)$ [M1A1]
$R$ has coordinates $\left(\frac{1}{2}\pi, 1 - \frac{1}{4}\pi\right)$ [A1A1] **4 marks**
4 (i) Sketch the graph of $y = \sqrt { 2 } \sin x$ for $0 \leqslant x \leqslant 2 \pi$.

The points $P$ and $Q$ on the graph have $x$-coordinates $\frac { 1 } { 4 } \pi$ and $\frac { 3 } { 4 } \pi$, respectively.\\
(ii) Determine the equation of the tangent to the curve at $P$.

The normals to the curve at $P$ and $Q$ intersect at the point $R$.\\
(iii) Determine the exact coordinates of $R$.

\hfill \mbox{\textit{Pre-U Pre-U 9794/1  Q4 [4]}}