| Exam Board | AQA |
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| Module | Paper 2 (Paper 2) |
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| Year | 2022 |
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| Session | June |
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| Topic | Non-constant acceleration |
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17 A particle is moving such that its position vector, \(\mathbf { r }\) metres, at time \(t\) seconds, is given by
$$\mathbf { r } = \mathrm { e } ^ { t } \cos t \mathbf { i } + \mathrm { e } ^ { t } \sin t \mathbf { j }$$
Show that the magnitude of the acceleration of the particle, \(a \mathrm {~ms} ^ { - 2 }\), is given by
$$a = 2 \mathrm { e } ^ { t }$$
Fully justify your answer.
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