AQA Paper 2 2022 June — Question 12 1 marks

Exam BoardAQA
ModulePaper 2 (Paper 2)
Year2022
SessionJune
Marks1
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicConstant acceleration (SUVAT)
TypeSUVAT single equation: straightforward find
DifficultyEasy -1.8 This is a straightforward one-step SUVAT problem requiring only the formula v = u + at with all values given directly. It's a multiple-choice question worth 1 mark involving simple algebraic substitution: 4u = u + 5a, so a = 0.6u. This is significantly easier than average A-level questions, requiring minimal problem-solving.
Spec3.02d Constant acceleration: SUVAT formulae

12 A car is travelling along a straight horizontal road with initial velocity \(u \mathrm {~m} \mathrm {~s} ^ { - 1 }\) The car begins to accelerate at a constant rate \(a \mathrm {~ms} ^ { - 2 }\) for 5 seconds, to reach a final velocity of \(4 u \mathrm {~m} \mathrm {~s} ^ { - 1 }\) Express \(a\) in terms of \(u\).
Circle your answer.
[0pt] [1 mark] \(a = 0.2 u\) \(a = 0.4 u\) \(a = 0.6 u\) \(a = 0.8 u\)

Question 12:
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(a = 0.6u\)B1 (1.1b)
## Question 12:

| Answer/Working | Marks | Guidance |
|---|---|---|
| $a = 0.6u$ | B1 (1.1b) | |
12 A car is travelling along a straight horizontal road with initial velocity $u \mathrm {~m} \mathrm {~s} ^ { - 1 }$\\
The car begins to accelerate at a constant rate $a \mathrm {~ms} ^ { - 2 }$ for 5 seconds, to reach a final velocity of $4 u \mathrm {~m} \mathrm {~s} ^ { - 1 }$

Express $a$ in terms of $u$.\\
Circle your answer.\\[0pt]
[1 mark]\\
$a = 0.2 u$\\
$a = 0.4 u$\\
$a = 0.6 u$\\
$a = 0.8 u$

\hfill \mbox{\textit{AQA Paper 2 2022 Q12 [1]}}