AQA Paper 1 2023 June — Question 8

Exam BoardAQA
ModulePaper 1 (Paper 1)
Year2023
SessionJune
TopicIntegration by Parts

8 Show that $$\int _ { 0 } ^ { \frac { \pi } { 2 } } ( x \sin 4 x ) \mathrm { d } x = - \frac { \pi } { 8 }$$
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