Moderate -0.8 This is a straightforward application of a standard transformation rule (horizontal stretch with scale factor k replaces x with x/k). It requires only recall of the transformation formula and one substitution step, making it easier than average but not trivial since students commonly confuse horizontal and vertical stretches.
3 The curve with equation \(y = \ln x\) is transformed by a stretch parallel to the \(x\)-axis with scale factor 2
Find the equation of the transformed curve.
Circle your answer.
\(y = \frac { 1 } { 2 } \ln x \quad y = 2 \ln x \quad y = \ln \frac { x } { 2 } \quad y = \ln 2 x\)
3 The curve with equation $y = \ln x$ is transformed by a stretch parallel to the $x$-axis with scale factor 2
Find the equation of the transformed curve.\\
Circle your answer.\\
$y = \frac { 1 } { 2 } \ln x \quad y = 2 \ln x \quad y = \ln \frac { x } { 2 } \quad y = \ln 2 x$
\hfill \mbox{\textit{AQA Paper 1 2023 Q3 [1]}}