AQA AS Paper 2 2021 June — Question 14 3 marks

Exam BoardAQA
ModuleAS Paper 2 (AS Paper 2)
Year2021
SessionJune
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicBinomial Distribution
TypeE(X) and Var(X) with probability calculations
DifficultyModerate -0.8 This is a straightforward binomial distribution question requiring only direct application of standard formulas (μ = np = 4.8, variance = np(1-p)) and calculator use for P(T ≤ 4.8) = P(T ≤ 4). No problem-solving or conceptual insight needed—pure routine calculation below average difficulty.
Spec2.04b Binomial distribution: as model B(n,p)2.04c Calculate binomial probabilities

14 The random variable \(T\) follows a binomial distribution where $$T \sim \mathrm {~B} ( 16,0.3 )$$ The mean of \(T\) is denoted by \(\mu\).
14
  1. \(\quad\) Find \(\mathrm { P } ( T \leq \mu )\).
    14
  2. Find the variance of \(T\). \includegraphics[max width=\textwidth, alt={}, center]{f87d1b36-26db-4a0b-b9ec-d7d82a396aba-19_2488_1716_219_153}

Question 14(a):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(\mu = np = 16 \times 0.3 = 4.8\)M1 (1.1a) Uses \(np\) to find \(\mu\); PI by 4.8
\(P(T \leq 4.8) = P(T \leq 4) = 0.4499\)A1 (3.4) AWRT 0.45
Question 14(b):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
Variance \(= 16 \times 0.3 \times 0.7 = 3.36\)B1 (1.1b) CAO
## Question 14(a):

| Answer/Working | Marks | Guidance |
|---|---|---|
| $\mu = np = 16 \times 0.3 = 4.8$ | M1 (1.1a) | Uses $np$ to find $\mu$; PI by 4.8 |
| $P(T \leq 4.8) = P(T \leq 4) = 0.4499$ | A1 (3.4) | AWRT 0.45 |

## Question 14(b):

| Answer/Working | Marks | Guidance |
|---|---|---|
| Variance $= 16 \times 0.3 \times 0.7 = 3.36$ | B1 (1.1b) | CAO |
14 The random variable $T$ follows a binomial distribution where

$$T \sim \mathrm {~B} ( 16,0.3 )$$

The mean of $T$ is denoted by $\mu$.\\
14
\begin{enumerate}[label=(\alph*)]
\item $\quad$ Find $\mathrm { P } ( T \leq \mu )$.\\

14
\item Find the variance of $T$.\\

\includegraphics[max width=\textwidth, alt={}, center]{f87d1b36-26db-4a0b-b9ec-d7d82a396aba-19_2488_1716_219_153}
\end{enumerate}

\hfill \mbox{\textit{AQA AS Paper 2 2021 Q14 [3]}}