AQA FP2 2009 January — Question 8 11 marks

Exam BoardAQA
ModuleFP2 (Further Pure Mathematics 2)
Year2009
SessionJanuary
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComplex numbers 2
Typenth roots via factorization
DifficultyStandard +0.8 This FP2 question requires students to verify an algebraic identity involving complex exponentials (routine), then apply it cleverly by recognizing that -1 = -2cos(2π/3) to factorize z^8 - z^4 + 1, and finally extract 8 roots using de Moivre's theorem. The key insight of matching coefficients to find θ = 2π/3 elevates this above standard root-finding exercises, though the techniques themselves are well-practiced at FP2 level.
Spec4.02k Argand diagrams: geometric interpretation4.02q De Moivre's theorem: multiple angle formulae4.02r nth roots: of complex numbers

8
  1. Show that $$\left( z ^ { 4 } - \mathrm { e } ^ { \mathrm { i } \theta } \right) \left( z ^ { 4 } - \mathrm { e } ^ { - \mathrm { i } \theta } \right) = z ^ { 8 } - 2 z ^ { 4 } \cos \theta + 1$$ (2 marks)
  2. Hence solve the equation $$z ^ { 8 } - z ^ { 4 } + 1 = 0$$ giving your answers in the form \(\mathrm { e } ^ { \mathrm { i } \phi }\), where \(- \pi < \phi \leqslant \pi\).
  3. Indicate the roots on an Argand diagram.

(a)
AnswerMarks Guidance
- Correct multiplication of bracketsM1
- \(e^{i\theta} + e^{-i\theta} = 2\cos\theta\)A1 2 marks; Clearly shown
- Total: 2 marks
(b)
AnswerMarks Guidance
- \(2\cos\theta = 1\)M1
- \(\theta = \frac{\pi}{3}\)A1
- \(z^4 = e^{\frac{\pi i}{3}}\) or \(e^{-\frac{\pi i}{3}}\)M1
- \(z = e^{\frac{\pi i}{12}}, e^{\frac{7\pi i}{12}}, e^{\frac{5\pi i}{12}}, e^{\frac{11\pi i}{12}}\)m1
-A2, 1, 0F 6 marks; Al if 3 roots correct
- Total: 6 marks
(c)
AnswerMarks Guidance
-B2, 1, 0 B1 for 4 roots indicated correctly on a circle. CAO
- Indication that \(r = 1\)B1 3 marks
- Total: 3 marks
Question 8 Total: 11 marks
GRAND TOTAL: 75 marks
**(a)**
- Correct multiplication of brackets | M1 |
- $e^{i\theta} + e^{-i\theta} = 2\cos\theta$ | A1 | 2 marks; Clearly shown
- **Total: 2 marks**

**(b)**
- $2\cos\theta = 1$ | M1 |
- $\theta = \frac{\pi}{3}$ | A1 |
- $z^4 = e^{\frac{\pi i}{3}}$ or $e^{-\frac{\pi i}{3}}$ | M1 |
- $z = e^{\frac{\pi i}{12}}, e^{\frac{7\pi i}{12}}, e^{\frac{5\pi i}{12}}, e^{\frac{11\pi i}{12}}$ | m1 |
- | A2, 1, 0F | 6 marks; Al if 3 roots correct
- **Total: 6 marks**

**(c)**
- | B2, 1, 0 | B1 for 4 roots indicated correctly on a circle. CAO
- Indication that $r = 1$ | B1 | 3 marks
- **Total: 3 marks**

**Question 8 Total: 11 marks**

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# **GRAND TOTAL: 75 marks**
8
\begin{enumerate}[label=(\alph*)]
\item Show that

$$\left( z ^ { 4 } - \mathrm { e } ^ { \mathrm { i } \theta } \right) \left( z ^ { 4 } - \mathrm { e } ^ { - \mathrm { i } \theta } \right) = z ^ { 8 } - 2 z ^ { 4 } \cos \theta + 1$$

(2 marks)
\item Hence solve the equation

$$z ^ { 8 } - z ^ { 4 } + 1 = 0$$

giving your answers in the form $\mathrm { e } ^ { \mathrm { i } \phi }$, where $- \pi < \phi \leqslant \pi$.
\item Indicate the roots on an Argand diagram.
\end{enumerate}

\hfill \mbox{\textit{AQA FP2 2009 Q8 [11]}}