Question 1 - A-Level Maths

Use the definitions $\sinh \theta = \frac { 1 } { 2 } \left( \mathrm { e } ^ { \theta } - \mathrm { e } ^ { - \theta } \right)$ and $\cosh \theta = \frac { 1 } { 2 } \left( \mathrm { e } ^ { \theta } + \mathrm { e } ^ { - \theta } \right)$ to show that $$1 + 2 \sinh ^ { 2 } \theta = \cosh 2 \theta$$
Solve the equation $$3 \cosh 2 \theta = 2 \sinh \theta + 11$$ giving each of your answers in the form $\ln p$.