AQA FP2 2008 January — Question 4 14 marks

Exam BoardAQA
ModuleFP2 (Further Pure Mathematics 2)
Year2008
SessionJanuary
Marks14
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicRoots of polynomials
TypeEquation with nonlinearly transformed roots
DifficultyStandard +0.3 This is a standard Further Maths question on Vieta's formulas and transformed roots. Part (a) is direct recall, part (b) uses standard algebraic identities (e.g., (α+β+γ)² = α²+β²+γ² + 2(αβ+βγ+γα)), and part (c) applies the standard technique of forming an equation from transformed roots. The complex coefficients add minimal difficulty since the algebraic manipulations are identical. This is slightly easier than average as it's a textbook exercise with well-rehearsed methods.
Spec4.05a Roots and coefficients: symmetric functions4.05b Transform equations: substitution for new roots

4 The cubic equation $$z ^ { 3 } + \mathrm { i } z ^ { 2 } + 3 z - ( 1 + \mathrm { i } ) = 0$$ has roots \(\alpha , \beta\) and \(\gamma\).
  1. Write down the value of:
    1. \(\alpha + \beta + \gamma\);
    2. \(\alpha \beta + \beta \gamma + \gamma \alpha\);
    3. \(\alpha \beta \gamma\).
  2. Find the value of:
    1. \(\alpha ^ { 2 } + \beta ^ { 2 } + \gamma ^ { 2 }\);
    2. \(\alpha ^ { 2 } \beta ^ { 2 } + \beta ^ { 2 } \gamma ^ { 2 } + \gamma ^ { 2 } \alpha ^ { 2 }\);
    3. \(\alpha ^ { 2 } \beta ^ { 2 } \gamma ^ { 2 }\).
  3. Hence write down a cubic equation whose roots are \(\alpha ^ { 2 } , \beta ^ { 2 }\) and \(\gamma ^ { 2 }\).

AnswerMarks Guidance
(a)(i) \(\sum \alpha = -i\)B1 1 mark
(ii) \(\sum \alpha\beta = 3\)B1 1 mark
(iii) \(\alpha\beta\gamma = 1 + i\)B1 1 mark
(b)(i) \(\sum \alpha^2 = (\sum \alpha)^2 - 2\sum \alpha\beta\) usedM1 Allow if sign error or 2 missing
\(= (-i)^2 - 2 \times 3\)A1F
\(= -7\)A1F 3 marks; ft errors in (a)
(ii) \(\sum \alpha^2\beta^2 = (\sum \alpha\beta)^2 - 2\alpha\beta\gamma\sum \alpha\)M1 Allow if sign error in 2 missing
\(= (\sum \alpha\beta)^2 - 2\alpha\beta\gamma\sum \alpha\)A1
\(= 9 - 2(1+i)(-i)\)A1F ft errors in (a)
\(= 7 + 2i\)A1F 4 marks; ft errors in (a)
(iii) \(\alpha^2\beta^2\gamma^2 = (1+i)^2 = 2i\)M1, A1F 2 marks; ft sign error in \(\alpha\beta\gamma\)
(c) \(z^3 + 7z^2 + (7 + 2i)z - 2i = 0\)B1F, B1F Correct numbers in correct places; Correct signs
2 marks
Question 4 Total: 14 marks
**(a)(i)** $\sum \alpha = -i$ | B1 | 1 mark

**(ii)** $\sum \alpha\beta = 3$ | B1 | 1 mark

**(iii)** $\alpha\beta\gamma = 1 + i$ | B1 | 1 mark

**(b)(i)** $\sum \alpha^2 = (\sum \alpha)^2 - 2\sum \alpha\beta$ used | M1 | Allow if sign error or 2 missing
$= (-i)^2 - 2 \times 3$ | A1F | 
$= -7$ | A1F | 3 marks; ft errors in (a)

**(ii)** $\sum \alpha^2\beta^2 = (\sum \alpha\beta)^2 - 2\alpha\beta\gamma\sum \alpha$ | M1 | Allow if sign error in 2 missing
$= (\sum \alpha\beta)^2 - 2\alpha\beta\gamma\sum \alpha$ | A1 | 
$= 9 - 2(1+i)(-i)$ | A1F | ft errors in (a)
$= 7 + 2i$ | A1F | 4 marks; ft errors in (a)

**(iii)** $\alpha^2\beta^2\gamma^2 = (1+i)^2 = 2i$ | M1, A1F | 2 marks; ft sign error in $\alpha\beta\gamma$

**(c)** $z^3 + 7z^2 + (7 + 2i)z - 2i = 0$ | B1F, B1F | Correct numbers in correct places; Correct signs
| | 2 marks

**Question 4 Total: 14 marks**

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4 The cubic equation

$$z ^ { 3 } + \mathrm { i } z ^ { 2 } + 3 z - ( 1 + \mathrm { i } ) = 0$$

has roots $\alpha , \beta$ and $\gamma$.
\begin{enumerate}[label=(\alph*)]
\item Write down the value of:
\begin{enumerate}[label=(\roman*)]
\item $\alpha + \beta + \gamma$;
\item $\alpha \beta + \beta \gamma + \gamma \alpha$;
\item $\alpha \beta \gamma$.
\end{enumerate}\item Find the value of:
\begin{enumerate}[label=(\roman*)]
\item $\alpha ^ { 2 } + \beta ^ { 2 } + \gamma ^ { 2 }$;
\item $\alpha ^ { 2 } \beta ^ { 2 } + \beta ^ { 2 } \gamma ^ { 2 } + \gamma ^ { 2 } \alpha ^ { 2 }$;
\item $\alpha ^ { 2 } \beta ^ { 2 } \gamma ^ { 2 }$.
\end{enumerate}\item Hence write down a cubic equation whose roots are $\alpha ^ { 2 } , \beta ^ { 2 }$ and $\gamma ^ { 2 }$.
\end{enumerate}

\hfill \mbox{\textit{AQA FP2 2008 Q4 [14]}}