AQA FP2 2008 January — Question 3 11 marks

Exam BoardAQA
ModuleFP2 (Further Pure Mathematics 2)
Year2008
SessionJanuary
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComplex Numbers Argand & Loci
TypeIntersection of two loci
DifficultyStandard +0.3 This is a straightforward Further Maths question requiring verification of two given facts (substitution and checking a point lies on a line through the centre), sketching standard loci (circle and half-line), and shading a region. All techniques are routine for FP2 students with no novel problem-solving required, making it slightly easier than average even for Further Maths.
Spec4.02k Argand diagrams: geometric interpretation4.02o Loci in Argand diagram: circles, half-lines

3 A circle \(C\) and a half-line \(L\) have equations $$| z - 2 \sqrt { 3 } - \mathrm { i } | = 4$$ and $$\arg ( z + i ) = \frac { \pi } { 6 }$$ respectively.
  1. Show that:
    1. the circle \(C\) passes through the point where \(z = - \mathrm { i }\);
    2. the half-line \(L\) passes through the centre of \(C\).
  2. On one Argand diagram, sketch \(C\) and \(L\).
  3. Shade on your sketch the set of points satisfying both $$| z - 2 \sqrt { 3 } - \mathrm { i } | \leqslant 4$$ and $$0 \leqslant \arg ( z + i ) \leqslant \frac { \pi } { 6 }$$

AnswerMarks Guidance
(a)(i) \(z = -i\)M1 \(
\(-2\sqrt{3} - 2i \)
\(4\)
(ii) Centre of circle is \(2\sqrt{3} + i\)B1 Do not accept \((2\sqrt{3}, 1)\) unless attempt to solve using trig
Substitute into lineM1
\(\arg(2\sqrt{3} + 2i) = \frac{\pi}{6}\) shownA1 3 marks
(b) Circle: centre correct through \((0, -1)\)B1
B1
Half line: through \((0, -1)\)B1
through centre of circleB1 4 marks
Shading inside circle and below lineB1F
Bounded by \(y = -1\)B1 2 marks
Question 3 Total: 11 marks
**(a)(i)** $z = -i$ | M1 | $|-2\sqrt{3} - 2i| = \sqrt{12 + 4} = 4$
$|-2\sqrt{3} - 2i|$ | A1 | 2 marks
$4$ | | 

**(ii)** Centre of circle is $2\sqrt{3} + i$ | B1 | Do not accept $(2\sqrt{3}, 1)$ unless attempt to solve using trig
Substitute into line | M1 | 
$\arg(2\sqrt{3} + 2i) = \frac{\pi}{6}$ shown | A1 | 3 marks

**(b)** Circle: centre correct through $(0, -1)$ | B1 | 
| B1 | 
Half line: through $(0, -1)$ | B1 | 
| through centre of circle | B1 | 4 marks
Shading inside circle and below line | B1F | 
Bounded by $y = -1$ | B1 | 2 marks

**Question 3 Total: 11 marks**

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3 A circle $C$ and a half-line $L$ have equations

$$| z - 2 \sqrt { 3 } - \mathrm { i } | = 4$$

and

$$\arg ( z + i ) = \frac { \pi } { 6 }$$

respectively.
\begin{enumerate}[label=(\alph*)]
\item Show that:
\begin{enumerate}[label=(\roman*)]
\item the circle $C$ passes through the point where $z = - \mathrm { i }$;
\item the half-line $L$ passes through the centre of $C$.
\end{enumerate}\item On one Argand diagram, sketch $C$ and $L$.
\item Shade on your sketch the set of points satisfying both

$$| z - 2 \sqrt { 3 } - \mathrm { i } | \leqslant 4$$

and

$$0 \leqslant \arg ( z + i ) \leqslant \frac { \pi } { 6 }$$
\end{enumerate}

\hfill \mbox{\textit{AQA FP2 2008 Q3 [11]}}