Easy -1.2 This is a straightforward application of conservation of momentum in one dimension with coalescence. Students simply need to apply m₁u₁ + m₂u₂ = (m₁+m₂)v with given values, requiring only basic algebraic manipulation. It's a standard textbook exercise with no problem-solving insight needed, making it easier than average.
1 Two particles, \(A\) and \(B\), are travelling in the same direction along a straight line on a smooth horizontal surface. Particle \(A\) has mass 3 kg and particle \(B\) has mass 7 kg . Particle \(A\) has a speed of \(20 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) and particle \(B\) has a speed of \(10 \mathrm {~m} \mathrm {~s} ^ { - 1 }\), as shown in the diagram.
\includegraphics[max width=\textwidth, alt={}, center]{fe8c1ea4-cf4d-4741-8af5-03e8c2c88559-2_186_835_653_593}
Particle \(A\) and particle \(B\) collide and coalesce to form a single particle. Find the speed of this single particle after the collision.
1 Two particles, $A$ and $B$, are travelling in the same direction along a straight line on a smooth horizontal surface. Particle $A$ has mass 3 kg and particle $B$ has mass 7 kg . Particle $A$ has a speed of $20 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ and particle $B$ has a speed of $10 \mathrm {~m} \mathrm {~s} ^ { - 1 }$, as shown in the diagram.\\
\includegraphics[max width=\textwidth, alt={}, center]{fe8c1ea4-cf4d-4741-8af5-03e8c2c88559-2_186_835_653_593}
Particle $A$ and particle $B$ collide and coalesce to form a single particle. Find the speed of this single particle after the collision.
\hfill \mbox{\textit{AQA M1 2010 Q1 [3]}}