| Exam Board | AQA |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2010 |
| Session | January |
| Marks | 5 |
| Paper | Download PDF ↗ |
| Topic | Motion on a slope |
| Type | Equilibrium on slope with force parallel to slope |
| Difficulty | Easy -1.2 This is a straightforward equilibrium problem on a slope requiring only basic resolution of forces (weight component perpendicular to slope for part b, parallel for part c). The question explicitly guides students through each step with no problem-solving insight needed—just routine application of N = mg cos θ and T = mg sin θ with given values. |
| Spec | 3.03b Newton's first law: equilibrium3.03e Resolve forces: two dimensions3.03m Equilibrium: sum of resolved forces = 0 |
3 A particle of mass 3 kg is on a smooth slope inclined at $60 ^ { \circ }$ to the horizontal. The particle is held at rest by a force of $T$ newtons parallel to the slope, as shown in the diagram.\\
\includegraphics[max width=\textwidth, alt={}, center]{fe8c1ea4-cf4d-4741-8af5-03e8c2c88559-2_337_284_2023_879}
\begin{enumerate}[label=(\alph*)]
\item Draw a diagram to show all the forces acting on the particle.
\item Show that the magnitude of the normal reaction acting on the particle is 14.7 newtons.
\item Find $T$.
\end{enumerate}
\hfill \mbox{\textit{AQA M1 2010 Q3 [5]}}