AQA C1 2007 January — Question 7 7 marks

Exam BoardAQA
ModuleC1 (Core Mathematics 1)
Year2007
SessionJanuary
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicInequalities
TypeQuadratic equation real roots
DifficultyModerate -0.3 This is a standard discriminant problem requiring students to apply b²-4ac ≥ 0 for real roots, then solve a quadratic inequality. While it involves multiple steps (forming discriminant, expanding, factorising, solving inequality), these are routine C1 techniques with no novel insight required, making it slightly easier than average.
Spec1.02d Quadratic functions: graphs and discriminant conditions

7 The quadratic equation \(( k + 1 ) x ^ { 2 } + 12 x + ( k - 4 ) = 0\) has real roots.
  1. Show that \(k ^ { 2 } - 3 k - 40 \leqslant 0\).
  2. Hence find the possible values of \(k\).

7(a)
AnswerMarks Guidance
\(b^2 - 4ac = 144 - 4(k + 1)(k - 4)\)M1 Clear attempt at \(b^2 - 4ac\); Condone slip in one term of expression
Real roots when \(b^2 - 4ac \geq 0\)
\(36 - (k^2 - 3k - 4) \geq 0\)
AnswerMarks Guidance
\(\Rightarrow k^2 - 3k - 40 \leq 0\)B1 Not just a statement, must involve \(k\); 3 marks
\(A1\)AG (watch signs carefully)
7(b)
AnswerMarks Guidance
\((k - 8)(k + 5)\)M1 Factors attempt or formula
Critical points \(8\) and \(-5\)A1
Sketch or sign diagram correct, must have \(8\) and \(-5\)
AnswerMarks Guidance
\(-5 \leq k \leq 8\)M1, A1 \(+\)ve \(
A0 for \(-5 < k < 8\) or two separate inequalities unless word AND used
Total: 7
GRAND TOTAL: 75
## 7(a)
$b^2 - 4ac = 144 - 4(k + 1)(k - 4)$ | M1 | Clear attempt at $b^2 - 4ac$; Condone slip in one term of expression

Real roots when $b^2 - 4ac \geq 0$
$36 - (k^2 - 3k - 4) \geq 0$
$\Rightarrow k^2 - 3k - 40 \leq 0$ | B1 | Not just a statement, must involve $k$; 3 marks

$A1$ | AG (watch signs carefully)

## 7(b)
$(k - 8)(k + 5)$ | M1 | Factors attempt or formula

Critical points $8$ and $-5$ | A1 | 

Sketch or sign diagram **correct, must have $8$ and $-5$**
$-5 \leq k \leq 8$ | M1, A1 | $+$ve $|$ $-$ve $|$ $+$ve with $-5$ and $8$ marked; 4 marks

A0 for $-5 < k < 8$ or two separate inequalities unless word AND used

**Total: 7**

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# **GRAND TOTAL: 75**
7 The quadratic equation $( k + 1 ) x ^ { 2 } + 12 x + ( k - 4 ) = 0$ has real roots.
\begin{enumerate}[label=(\alph*)]
\item Show that $k ^ { 2 } - 3 k - 40 \leqslant 0$.
\item Hence find the possible values of $k$.
\end{enumerate}

\hfill \mbox{\textit{AQA C1 2007 Q7 [7]}}