OCR H240/01 2018 March — Question 1 4 marks

Exam BoardOCR
ModuleH240/01 (Pure Mathematics)
Year2018
SessionMarch
Marks4
TopicCircles
TypeFind centre and radius from equation
DifficultyEasy -1.2 This is a straightforward application of completing the square to find circle centre and radius. Part (i) requires only rearranging to standard form (no calculation needed since k is unknown), and part (ii) involves simple algebra to find k given the radius. This is a standard textbook exercise testing basic recall of circle equation manipulation with minimal problem-solving required.
Spec1.03d Circles: equation (x-a)^2+(y-b)^2=r^21.03e Complete the square: find centre and radius of circle

1 A circle with equation \(x ^ { 2 } + y ^ { 2 } + 6 x - 4 y = k\) has a radius of 4 .
  1. Find the coordinates of the centre of the circle.
  2. Find the value of the constant \(k\).

(i)
AnswerMarks Guidance
\((x + 3)^2 + (y + 2)^2 = \ldots\) with centre \((-3, 2)\)M1, A1 Attempt to complete the square; State correct centre www; Ignore constant term(s)
(ii)
AnswerMarks Guidance
\(13 + k = 16\), \(k = 3\)M1, A1 Attempt to link 9, 4, 16 and \(k\); Obtain \(k = 3\)
**(i)** 
| $(x + 3)^2 + (y + 2)^2 = \ldots$ with centre $(-3, 2)$ | M1, A1 | Attempt to complete the square; State correct centre www; Ignore constant term(s) |

**(ii)**
| $13 + k = 16$, $k = 3$ | M1, A1 | Attempt to link 9, 4, 16 and $k$; Obtain $k = 3$ |
1 A circle with equation $x ^ { 2 } + y ^ { 2 } + 6 x - 4 y = k$ has a radius of 4 .\\
(i) Find the coordinates of the centre of the circle.\\
(ii) Find the value of the constant $k$.

\hfill \mbox{\textit{OCR H240/01 2018 Q1 [4]}}