Edexcel CP AS 2023 June — Question 2 7 marks

Exam BoardEdexcel
ModuleCP AS (Core Pure AS)
Year2023
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicRoots of polynomials
TypeComplex roots with real coefficients
DifficultyStandard +0.3 This is a standard Core Pure question testing the conjugate root theorem and basic polynomial manipulation. Part (a) requires using the fact that complex roots come in conjugate pairs for real coefficients, then finding the third root and using Vieta's formulas or expansion. Parts (b) and (c) are routine applications. While it requires multiple steps, all techniques are standard textbook exercises with no novel insight needed, making it slightly easier than average.
Spec4.02g Conjugate pairs: real coefficient polynomials4.02k Argand diagrams: geometric interpretation

  1. \(\mathrm { f } ( \mathrm { z } ) = \mathrm { z } ^ { 3 } + a \mathrm { z } ^ { 2 } + b \mathrm { z } + 175 \quad\) where \(a\) and \(b\) are real constants
Given that \(- 3 + 4 \mathrm { i }\) is a root of the equation \(\mathrm { f } ( \mathrm { z } ) = 0\)
  1. determine the value of \(a\) and the value of \(b\).
  2. Show all the roots of the equation \(\mathrm { f } ( \mathrm { z } ) = 0\) on a single Argand diagram.
  3. Write down the roots of the equation \(\mathrm { f } ( \mathrm { z } + 2 ) = 0\)

Question 2(a):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(z^* = -3 - 4i\); uses \((z-(-3+4i))(z-(-3-4i)) = z^2 + pz + q\); writes \(f(z) = (z^2+pz+q)(z+r)\)M1 3.1a
\((z^2+6z+25)(z+7)\)A1 1.1b
Multiplies out \((z^2+6z+25)(z+7) = \alpha z^2 + \beta z \ldots\)M1 1.1b
\(z^3+13z^2+67z+175\) or \(a=13, b=67\)A1 1.1b
Alternative 1:
AnswerMarks Guidance
Answer/WorkingMark Guidance
Uses complex conjugate and product of roots \(= -175\) to find third rootM1 3.1a
Third root \(= -7\)A1 1.1b
Uses sum of roots \(= -a\) to find \(a\) or uses pair sum \(= b\) to find \(b\); or expands \((z-(-3+4i))(z-(-3-4i))(z-\text{their third root})\)M1 1.1b
\(a=13, b=67\)A1 1.1b
Alternative 2:
AnswerMarks Guidance
Answer/WorkingMark Guidance
\((-3+4i)^3 + a(-3+4i)^2 + b(-3+4i)+175=0 \Rightarrow 117+44i+a(-7-24i)+b(-3+4i)+175=0\); equates real and imaginary parts to form two linear simultaneous equationsM1 3.1a
\(117-7a-3b+175=0 \Rightarrow -7a-3b=-292\); \(44-24a+4b=0 \Rightarrow -24a+4b=-44\)A1 1.1b
Solves simultaneously to find values for \(a\) or \(b\)M1 1.1b
\(a=13, b=67\)A1 1.1b
Question 2(b):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Correctly plotting \(-3+4i,\ -3-4i\)B1 1.1b
Correctly plotting \(-7\)B1 2.2a
Question 2(c):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(-5+4i,\ -5-4i,\ -9\)B1ft 2.2a — ft: \(-5+4i\), \(-5-4i\) and subtracts 2 from real root shown on Argand diagram
## Question 2(a):

| Answer/Working | Mark | Guidance |
|---|---|---|
| $z^* = -3 - 4i$; uses $(z-(-3+4i))(z-(-3-4i)) = z^2 + pz + q$; writes $f(z) = (z^2+pz+q)(z+r)$ | M1 | 3.1a |
| $(z^2+6z+25)(z+7)$ | A1 | 1.1b |
| Multiplies out $(z^2+6z+25)(z+7) = \alpha z^2 + \beta z \ldots$ | M1 | 1.1b |
| $z^3+13z^2+67z+175$ or $a=13, b=67$ | A1 | 1.1b |

**Alternative 1:**

| Answer/Working | Mark | Guidance |
|---|---|---|
| Uses complex conjugate and product of roots $= -175$ to find third root | M1 | 3.1a |
| Third root $= -7$ | A1 | 1.1b |
| Uses sum of roots $= -a$ to find $a$ **or** uses pair sum $= b$ to find $b$; **or** expands $(z-(-3+4i))(z-(-3-4i))(z-\text{their third root})$ | M1 | 1.1b |
| $a=13, b=67$ | A1 | 1.1b |

**Alternative 2:**

| Answer/Working | Mark | Guidance |
|---|---|---|
| $(-3+4i)^3 + a(-3+4i)^2 + b(-3+4i)+175=0 \Rightarrow 117+44i+a(-7-24i)+b(-3+4i)+175=0$; equates real and imaginary parts to form two linear simultaneous equations | M1 | 3.1a |
| $117-7a-3b+175=0 \Rightarrow -7a-3b=-292$; $44-24a+4b=0 \Rightarrow -24a+4b=-44$ | A1 | 1.1b |
| Solves simultaneously to find values for $a$ or $b$ | M1 | 1.1b |
| $a=13, b=67$ | A1 | 1.1b |

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## Question 2(b):

| Answer/Working | Mark | Guidance |
|---|---|---|
| Correctly plotting $-3+4i,\ -3-4i$ | B1 | 1.1b |
| Correctly plotting $-7$ | B1 | 2.2a |

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## Question 2(c):

| Answer/Working | Mark | Guidance |
|---|---|---|
| $-5+4i,\ -5-4i,\ -9$ | B1ft | 2.2a — ft: $-5+4i$, $-5-4i$ and subtracts 2 from real root shown on Argand diagram |

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\begin{enumerate}
  \item $\mathrm { f } ( \mathrm { z } ) = \mathrm { z } ^ { 3 } + a \mathrm { z } ^ { 2 } + b \mathrm { z } + 175 \quad$ where $a$ and $b$ are real constants
\end{enumerate}

Given that $- 3 + 4 \mathrm { i }$ is a root of the equation $\mathrm { f } ( \mathrm { z } ) = 0$\\
(a) determine the value of $a$ and the value of $b$.\\
(b) Show all the roots of the equation $\mathrm { f } ( \mathrm { z } ) = 0$ on a single Argand diagram.\\
(c) Write down the roots of the equation $\mathrm { f } ( \mathrm { z } + 2 ) = 0$

\hfill \mbox{\textit{Edexcel CP AS 2023 Q2 [7]}}