Edexcel CP AS 2023 June — Question 3 4 marks

Exam BoardEdexcel
ModuleCP AS (Core Pure AS)
Year2023
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicLinear transformations
TypeCombined transformation matrix product
DifficultyModerate -0.3 This is a straightforward Core Pure AS question on 3D transformations requiring: (a) recognition of a rotation matrix about the x-axis by 30°, (b) identifying the common error of multiplying matrices in the wrong order (should be BA not AB), and (c) performing a 3×3 matrix multiplication with some surds. All parts are standard bookwork with no novel problem-solving required, making it slightly easier than average.
Spec4.03b Matrix operations: addition, multiplication, scalar4.03d Linear transformations 2D: reflection, rotation, enlargement, shear

3. $$\mathbf { A } = \left( \begin{array} { c c c } 1 & 0 & 0 \\ 0 & \frac { \sqrt { 3 } } { 2 } & - \frac { 1 } { 2 } \\ 0 & \frac { 1 } { 2 } & \frac { \sqrt { 3 } } { 2 } \end{array} \right)$$
  1. Describe fully the single geometric transformation \(A\) represented by the matrix \(\mathbf { A }\). $$\mathbf { B } = \left( \begin{array} { c c c } 1 & 3 & 0 \\ \sqrt { 3 } & 0 & 5 \sqrt { 3 } \\ 1 & 2 & 0 \end{array} \right)$$ The transformation \(B\) is represented by the matrix \(\mathbf { B }\).
    The transformation \(A\) followed by the transformation \(B\) is the transformation \(C\), which is represented by the matrix \(\mathbf { C }\). To determine matrix \(\mathbf { C }\), a student attempts the following matrix multiplication. $$\left( \begin{array} { c c c } 1 & 0 & 0 \\ 0 & \frac { \sqrt { 3 } } { 2 } & - \frac { 1 } { 2 } \\ 0 & \frac { 1 } { 2 } & \frac { \sqrt { 3 } } { 2 } \end{array} \right) \left( \begin{array} { c c c } 1 & 3 & 0 \\ \sqrt { 3 } & 0 & 5 \sqrt { 3 } \\ 1 & 2 & 0 \end{array} \right)$$
  2. State the error made by the student.
  3. Determine the correct matrix \(\mathbf { C }\).

Question 3(a):
AnswerMarks Guidance
Answer/WorkingMark Guidance
RotationB1 1.1b — identifies single transformation as rotation only
\(30\) degrees or \(\frac{\pi}{6}\) about the \(x\)-axis; ignore any reference to directionB1 1.1b — correct angle and axis; note: \(x\)-plane, \(zy\)-plane and \(x=0\) are 2nd B0; any additional incorrect statements is 2nd B0
Question 3(b):
AnswerMarks Guidance
Answer/WorkingMark Guidance
They have found \(\mathbf{AB}\) when they should find \(\mathbf{BA}\); multiplication is the wrong way round; it should be \(\mathbf{BA}\); matrix \(B\) should be on the left; student has done transformation \(B\) followed by transformation \(A\). It should be \(\begin{pmatrix}1&3&0\\\sqrt{3}&0&5\sqrt{3}\\1&2&0\end{pmatrix}\begin{pmatrix}1&0&0\\0&\frac{\sqrt{3}}{2}&-\frac{1}{2}\\0&\frac{1}{2}&\frac{\sqrt{3}}{2}\end{pmatrix}\)B1 2.3 — explains matrices should be multiplied the other way around
Question 3(c):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(\begin{pmatrix}1&3&0\\\sqrt{3}&0&5\sqrt{3}\\1&2&0\end{pmatrix}\begin{pmatrix}1&0&0\\0&\frac{\sqrt{3}}{2}&-\frac{1}{2}\\0&\frac{1}{2}&\frac{\sqrt{3}}{2}\end{pmatrix} = \begin{pmatrix}1&\frac{3\sqrt{3}}{2}&-\frac{3}{2}\\\sqrt{3}&\frac{5\sqrt{3}}{2}&\frac{15}{2}\\1&\sqrt{3}&-1\end{pmatrix}\)B1 1.1b — correct exact matrix; note \(5\sqrt{3}\times\frac{\sqrt{3}}{2}\) must simplify to \(\frac{15}{2}\); condone \(\frac{2\sqrt{3}}{2}\) not simplified
## Question 3(a):

| Answer/Working | Mark | Guidance |
|---|---|---|
| Rotation | B1 | 1.1b — identifies single transformation as rotation only |
| $30$ degrees or $\frac{\pi}{6}$ about the $x$-axis; ignore any reference to direction | B1 | 1.1b — correct angle and axis; note: $x$-plane, $zy$-plane and $x=0$ are 2nd B0; any additional incorrect statements is 2nd B0 |

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## Question 3(b):

| Answer/Working | Mark | Guidance |
|---|---|---|
| They have found $\mathbf{AB}$ when they should find $\mathbf{BA}$; multiplication is the wrong way round; it should be $\mathbf{BA}$; matrix $B$ should be on the left; student has done transformation $B$ followed by transformation $A$. It should be $\begin{pmatrix}1&3&0\\\sqrt{3}&0&5\sqrt{3}\\1&2&0\end{pmatrix}\begin{pmatrix}1&0&0\\0&\frac{\sqrt{3}}{2}&-\frac{1}{2}\\0&\frac{1}{2}&\frac{\sqrt{3}}{2}\end{pmatrix}$ | B1 | 2.3 — explains matrices should be multiplied the other way around |

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## Question 3(c):

| Answer/Working | Mark | Guidance |
|---|---|---|
| $\begin{pmatrix}1&3&0\\\sqrt{3}&0&5\sqrt{3}\\1&2&0\end{pmatrix}\begin{pmatrix}1&0&0\\0&\frac{\sqrt{3}}{2}&-\frac{1}{2}\\0&\frac{1}{2}&\frac{\sqrt{3}}{2}\end{pmatrix} = \begin{pmatrix}1&\frac{3\sqrt{3}}{2}&-\frac{3}{2}\\\sqrt{3}&\frac{5\sqrt{3}}{2}&\frac{15}{2}\\1&\sqrt{3}&-1\end{pmatrix}$ | B1 | 1.1b — correct exact matrix; note $5\sqrt{3}\times\frac{\sqrt{3}}{2}$ must simplify to $\frac{15}{2}$; condone $\frac{2\sqrt{3}}{2}$ not simplified |

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3.

$$\mathbf { A } = \left( \begin{array} { c c c } 
1 & 0 & 0 \\
0 & \frac { \sqrt { 3 } } { 2 } & - \frac { 1 } { 2 } \\
0 & \frac { 1 } { 2 } & \frac { \sqrt { 3 } } { 2 }
\end{array} \right)$$
\begin{enumerate}[label=(\alph*)]
\item Describe fully the single geometric transformation $A$ represented by the matrix $\mathbf { A }$.

$$\mathbf { B } = \left( \begin{array} { c c c } 
1 & 3 & 0 \\
\sqrt { 3 } & 0 & 5 \sqrt { 3 } \\
1 & 2 & 0
\end{array} \right)$$

The transformation $B$ is represented by the matrix $\mathbf { B }$.\\
The transformation $A$ followed by the transformation $B$ is the transformation $C$, which is represented by the matrix $\mathbf { C }$.

To determine matrix $\mathbf { C }$, a student attempts the following matrix multiplication.

$$\left( \begin{array} { c c c } 
1 & 0 & 0 \\
0 & \frac { \sqrt { 3 } } { 2 } & - \frac { 1 } { 2 } \\
0 & \frac { 1 } { 2 } & \frac { \sqrt { 3 } } { 2 }
\end{array} \right) \left( \begin{array} { c c c } 
1 & 3 & 0 \\
\sqrt { 3 } & 0 & 5 \sqrt { 3 } \\
1 & 2 & 0
\end{array} \right)$$
\item State the error made by the student.
\item Determine the correct matrix $\mathbf { C }$.
\end{enumerate}

\hfill \mbox{\textit{Edexcel CP AS 2023 Q3 [4]}}