AQA Further Paper 3 Discrete Specimen — Question 4 3 marks

Exam BoardAQA
ModuleFurther Paper 3 Discrete (Further Paper 3 Discrete)
SessionSpecimen
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMinimum Spanning Trees
TypeCalculate MST length/weight/cost
DifficultyModerate -0.8 This is a straightforward application of Kruskal's or Prim's algorithm to find an MST with only 5 vertices. The table is clearly presented, the algorithm is mechanical, and no problem-solving insight is required—just systematic application of a standard procedure taught in Decision Maths.
Spec7.04b Minimum spanning tree: Prim's and Kruskal's algorithms

4 Optical fibre broadband cables are being installed between 5 neighbouring villages. The distance between each pair of villages in metres is shown in the table.
AlvanleyDunhamEltonHelsbyInce
Alvanley-200040007505500
Dunham2000-250022504000
Elton40002500-30001250
Helsby75022503000-4250
Ince5500400012504250-
The company installing the optical fibre broadband cables wishes to create a network connecting each of the 5 villages using the minimum possible length of cable. Find the minimum length of cable required.
[0pt] [3 marks]

Question 4:
AnswerMarks Guidance
AnswerMark Guidance
Translates problem into finding a minimum spanning tree by listing or drawing 4 labelled arcsM1 Condone A for Alvanley etc
Alvanley to Helsby: 750, Elton to Ince: 1250, Alvanley to Dunham: 2000, Dunham to Elton: 2500A1 Finds correctly 4 arcs of the minimum spanning tree by listing or drawing
\(750 + 1250 + 2000 + 2500 = 6500\) mB1 Determines correctly the total minimum length of cable required, complete with unit
## Question 4:

| Answer | Mark | Guidance |
|--------|------|----------|
| Translates problem into finding a minimum spanning tree by listing or drawing 4 labelled arcs | M1 | Condone A for Alvanley etc |
| Alvanley to Helsby: 750, Elton to Ince: 1250, Alvanley to Dunham: 2000, Dunham to Elton: 2500 | A1 | Finds correctly 4 arcs of the minimum spanning tree by listing or drawing |
| $750 + 1250 + 2000 + 2500 = 6500$ m | B1 | Determines correctly the total minimum length of cable required, complete with unit |

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4 Optical fibre broadband cables are being installed between 5 neighbouring villages.

The distance between each pair of villages in metres is shown in the table.

\begin{center}
\begin{tabular}{|l|l|l|l|l|l|}
\hline
 & Alvanley & Dunham & Elton & Helsby & Ince \\
\hline
Alvanley & - & 2000 & 4000 & 750 & 5500 \\
\hline
Dunham & 2000 & - & 2500 & 2250 & 4000 \\
\hline
Elton & 4000 & 2500 & - & 3000 & 1250 \\
\hline
Helsby & 750 & 2250 & 3000 & - & 4250 \\
\hline
Ince & 5500 & 4000 & 1250 & 4250 & - \\
\hline
\end{tabular}
\end{center}

The company installing the optical fibre broadband cables wishes to create a network connecting each of the 5 villages using the minimum possible length of cable.

Find the minimum length of cable required.\\[0pt]
[3 marks]

\hfill \mbox{\textit{AQA Further Paper 3 Discrete  Q4 [3]}}