OCR MEI Further Statistics Minor 2021 November — Question 6 7 marks

Exam BoardOCR MEI
ModuleFurther Statistics Minor (Further Statistics Minor)
Year2021
SessionNovember
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicUniform Distribution
TypeCalculate basic probabilities
DifficultyStandard +0.3 This is a straightforward application of discrete uniform distribution properties. Part (a) requires basic counting and probability calculation with simple floor function considerations, while part (b) involves standard formulas for mean and standard deviation of uniform distributions. The question is slightly above average due to the algebraic manipulation in (a)(ii) and the need to recall/derive uniform distribution formulas, but remains a standard textbook exercise with no novel problem-solving required.
Spec5.02e Discrete uniform distribution5.03b Solve problems: using pdf5.03c Calculate mean/variance: by integration

6 A lottery has tickets numbered 1 to \(n\) inclusive, where \(n\) is a positive integer. The random variable \(X\) denotes the number on a ticket drawn at random.
  1. Determine \(\mathrm { P } \left( \mathrm { X } \leqslant \frac { 1 } { 4 } \mathrm { n } \right)\) in each of the following cases.
    1. \(n\) is a multiple of 4 .
    2. \(n\) is of the form \(4 k + 1\), where \(k\) is a positive integer. Give your answer as a single fraction in terms of \(n\).
  2. Given that \(n = 101\), find the probability that \(X\) is within one standard deviation of the mean.

Question 6:
AnswerMarks Guidance
6(a) (i)
P ( X ≤ 1n )= 1
AnswerMarks Guidance
4 4B1
[1]3.3
6(a) (ii)
P ( X ≤ 1n )=
4 4k+1
1(n−1)
= 4
n
n−1
=
AnswerMarks
4nM1
M1
A1
AnswerMarks
[3]2.2a
1.1
AnswerMarks
1.1Single fraction
required for A1
AnswerMarks Guidance
6(b) E(X) = 51 Var(X) = 850
SD(X) = 29.1 So require P(21.9 < X < 80.1)
P(22≤ X ≤80)= 59
AnswerMarks
101M1
M1
A1
AnswerMarks
[3]3.1b
1.1a
AnswerMarks
1.1For either
For required interval
PMT
OCR (Oxford Cambridge and RSA Examinations)
The Triangle Building
Shaftesbury Road
Cambridge
CB2 8EA
OCR Customer Contact Centre
Education and Learning
Telephone: 01223 553998
Facsimile: 01223 552627
Email: general.qualifications@ocr.org.uk
www.ocr.org.uk
For staff training purposes and as part of our quality assurance programme your call may be
recorded or monitored
Question 6:
6 | (a) | (i) | Uniform distribution on {1, 2, … , n}
P ( X ≤ 1n )= 1
4 4 | B1
[1] | 3.3
6 | (a) | (ii) | k
P ( X ≤ 1n )=
4 4k+1
1(n−1)
= 4
n
n−1
=
4n | M1
M1
A1
[3] | 2.2a
1.1
1.1 | Single fraction
required for A1
6 | (b) | E(X) = 51 Var(X) = 850
SD(X) = 29.1 So require P(21.9 < X < 80.1)
P(22≤ X ≤80)= 59
101 | M1
M1
A1
[3] | 3.1b
1.1a
1.1 | For either
For required interval
PMT
OCR (Oxford Cambridge and RSA Examinations)
The Triangle Building
Shaftesbury Road
Cambridge
CB2 8EA
OCR Customer Contact Centre
Education and Learning
Telephone: 01223 553998
Facsimile: 01223 552627
Email: general.qualifications@ocr.org.uk
www.ocr.org.uk
For staff training purposes and as part of our quality assurance programme your call may be
recorded or monitored
6 A lottery has tickets numbered 1 to $n$ inclusive, where $n$ is a positive integer. The random variable $X$ denotes the number on a ticket drawn at random.
\begin{enumerate}[label=(\alph*)]
\item Determine $\mathrm { P } \left( \mathrm { X } \leqslant \frac { 1 } { 4 } \mathrm { n } \right)$ in each of the following cases.
\begin{enumerate}[label=(\roman*)]
\item $n$ is a multiple of 4 .
\item $n$ is of the form $4 k + 1$, where $k$ is a positive integer. Give your answer as a single fraction in terms of $n$.
\end{enumerate}\item Given that $n = 101$, find the probability that $X$ is within one standard deviation of the mean.
\end{enumerate}

\hfill \mbox{\textit{OCR MEI Further Statistics Minor 2021 Q6 [7]}}