| Exam Board | OCR MEI |
|---|---|
| Module | Further Mechanics Minor (Further Mechanics Minor) |
| Year | 2024 |
| Session | June |
| Marks | 5 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Work done and energy |
| Type | Work-energy over time interval |
| Difficulty | Standard +0.3 This is a straightforward application of the work-energy principle with constant power. Part (a) uses Power × time = change in KE (standard formula manipulation), and part (b) requires P = Fv then F = ma. Both parts are direct applications of standard mechanics formulas with no conceptual obstacles or multi-step reasoning required. |
| Spec | 6.02k Power: rate of doing work6.02l Power and velocity: P = Fv |
| Answer | Marks | Guidance |
|---|---|---|
| 1 | (a) | Gain in kinetic energy |
| Answer | Marks |
|---|---|
| t = 7 5 | M1 |
| Answer | Marks |
|---|---|
| [3] | 3.3 |
| Answer | Marks |
|---|---|
| 1.1 | Attempt to find the change in |
| Answer | Marks |
|---|---|
| (b) | D r i v i n g f o r c e = 5 0 0 0 2 5 ( = 2 0 0 ) |
| So a = 2 0 0 1 5 0 0 = 0 .1 3 ( 3 3 3 ) | B1 |
| Answer | Marks |
|---|---|
| [2] | 3.3 |
| 1.1 | soi |
Question 1:
1 | (a) | Gain in kinetic energy
= 12 1 5 0 0 3 0 2 − 12 1 5 0 0 2 0 2 (=375000)
5 0 0 0 t = 3 7 5 0 0 0
t = 7 5 | M1
M1
A1
[3] | 3.3
1.1
1.1 | Attempt to find the change in
kinetic energy.
Attempt at considering power as
rate of work done.
(b) | D r i v i n g f o r c e = 5 0 0 0 2 5 ( = 2 0 0 )
So a = 2 0 0 1 5 0 0 = 0 .1 3 ( 3 3 3 ) | B1
B1
[2] | 3.3
1.1 | soi
21
Accept
51 A car of mass 1500 kg travels along a horizontal straight road. There are no resistances to the car's motion. The power developed by the car as it increases its speed from $20 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ to $30 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ over $t$ seconds is a constant 5000 W .
\begin{enumerate}[label=(\alph*)]
\item Determine the value of $t$.
\item Find the acceleration of the car when its speed is $25 \mathrm {~m} \mathrm {~s} ^ { - 1 }$.
\end{enumerate}
\hfill \mbox{\textit{OCR MEI Further Mechanics Minor 2024 Q1 [5]}}