AQA FP1 2013 June — Question 5 8 marks

Exam BoardAQA
ModuleFP1 (Further Pure Mathematics 1)
Year2013
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicDifferentiation from First Principles
TypeStationary point via first principles
DifficultyStandard +0.3 Part (a) is a straightforward application of first principles differentiation using the chord gradient formula, requiring only substitution and simplification to show the gradient is 2h-1, then taking the limit as h→0. Part (b) is a standard improper integral evaluation. Both parts are routine FP1 exercises requiring careful algebra but no novel insight or complex problem-solving.
Spec1.02d Quadratic functions: graphs and discriminant conditions1.07a Derivative as gradient: of tangent to curve1.08a Fundamental theorem of calculus: integration as reverse of differentiation4.08c Improper integrals: infinite limits or discontinuous integrands

5
  1. A curve has equation \(y = 2 x ^ { 2 } - 5 x\).
    The point \(P\) on the curve has coordinates \(( 1 , - 3 )\).
    The point \(Q\) on the curve has \(x\)-coordinate \(1 + h\).
    1. Show that the gradient of the line \(P Q\) is \(2 h - 1\).
    2. Explain how the result of part (a)(i) can be used to show that the tangent to the curve at the point \(P\) is parallel to the line \(x + y = 0\).
  2. For the improper integral \(\int _ { 1 } ^ { \infty } x ^ { - 4 } \left( 2 x ^ { 2 } - 5 x \right) \mathrm { d } x\), either show that the integral has a finite value and state its value, or explain why the integral does not have a finite value.

(a) A curve has equation \(y = 2x^2 - 5x\).
The point \(P\) on the curve has coordinates \((1, -3)\).
The point \(Q\) on the curve has \(x\)-coordinate \(1 + h\).
(i) Show that the gradient of the line \(PQ\) is \(2h - 1\). (3 marks)
(ii) Explain how the result of part (a)(i) can be used to show that the tangent to the curve at the point \(P\) is parallel to the line \(x + y = 0\). (2 marks)
(b) For the improper integral
\[\int_1^{\infty} \frac{x - 4}{2x^2 - 5x} \, dx\]
either show that the integral has a finite value and state its value, or explain why the integral does not have a finite value. (3 marks)
**(a) A curve has equation $y = 2x^2 - 5x$.**

The point $P$ on the curve has coordinates $(1, -3)$.

The point $Q$ on the curve has $x$-coordinate $1 + h$.

(i) Show that the gradient of the line $PQ$ is $2h - 1$. **(3 marks)**

(ii) Explain how the result of part (a)(i) can be used to show that the tangent to the curve at the point $P$ is parallel to the line $x + y = 0$. **(2 marks)**

**(b) For the improper integral**
$$\int_1^{\infty} \frac{x - 4}{2x^2 - 5x} \, dx$$

**either show that the integral has a finite value and state its value, or explain why the integral does not have a finite value. (3 marks)**
5
\begin{enumerate}[label=(\alph*)]
\item A curve has equation $y = 2 x ^ { 2 } - 5 x$.\\
The point $P$ on the curve has coordinates $( 1 , - 3 )$.\\
The point $Q$ on the curve has $x$-coordinate $1 + h$.
\begin{enumerate}[label=(\roman*)]
\item Show that the gradient of the line $P Q$ is $2 h - 1$.
\item Explain how the result of part (a)(i) can be used to show that the tangent to the curve at the point $P$ is parallel to the line $x + y = 0$.
\end{enumerate}\item For the improper integral $\int _ { 1 } ^ { \infty } x ^ { - 4 } \left( 2 x ^ { 2 } - 5 x \right) \mathrm { d } x$, either show that the integral has a finite value and state its value, or explain why the integral does not have a finite value.
\end{enumerate}

\hfill \mbox{\textit{AQA FP1 2013 Q5 [8]}}