AQA FP1 2011 June — Question 6 7 marks

Exam BoardAQA
ModuleFP1 (Further Pure Mathematics 1)
Year2011
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicDifferentiation from First Principles
TypeExpand f(a+h) algebraically
DifficultyModerate -0.8 This is a guided, multi-step differentiation from first principles question where part (a) scaffolds the algebra needed for part (b). The expansion of (5+h)³ is straightforward binomial expansion, and part (b) follows a standard template: substitute x=5+h, find the difference quotient, and take the limit as h→0. While it requires careful algebraic manipulation, the question provides significant structure and all steps are routine for Further Maths students who have practiced this technique.
Spec1.07g Differentiation from first principles: for small positive integer powers of x

6
  1. Expand \(( 5 + h ) ^ { 3 }\).
  2. A curve has equation \(y = x ^ { 3 } - x ^ { 2 }\).
    1. Find the gradient of the line passing through the point \(( 5,100 )\) and the point on the curve for which \(x = 5 + h\). Give your answer in the form $$p + q h + r h ^ { 2 }$$ where \(p , q\) and \(r\) are integers.
    2. Show how the answer to part (b)(i) can be used to find the gradient of the curve at the point \(( 5,100 )\). State the value of this gradient.

Question 6:
Part (a):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\((5+h)^3 = 125 + 75h + 15h^2 + h^3\)B1 Accept unsimplified coefficients
Total1
Part (b)(i):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(y(5+h) = 100 + 65h + 14h^2 + h^3\)B1F PI; ft numerical error in (a)
Use of correct formula for gradientM1
Gradient is \(65 + 14h + h^2\)A2,1F A1 if one numerical error made; ft numerical error already penalised
Total4
Part (b)(ii):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
As \(h \to 0\) this \(\to 65\)E2,1F E1 for '\(h = 0\)'; ft wrong values for \(p, q, r\)
Total2
## Question 6:

### Part (a):
| Answer/Working | Marks | Guidance |
|---|---|---|
| $(5+h)^3 = 125 + 75h + 15h^2 + h^3$ | B1 | Accept unsimplified coefficients |
| **Total** | **1** | |

### Part (b)(i):
| Answer/Working | Marks | Guidance |
|---|---|---|
| $y(5+h) = 100 + 65h + 14h^2 + h^3$ | B1F | PI; ft numerical error in (a) |
| Use of correct formula for gradient | M1 | |
| Gradient is $65 + 14h + h^2$ | A2,1F | A1 if one numerical error made; ft numerical error already penalised |
| **Total** | **4** | |

### Part (b)(ii):
| Answer/Working | Marks | Guidance |
|---|---|---|
| As $h \to 0$ this $\to 65$ | E2,1F | E1 for '$h = 0$'; ft wrong values for $p, q, r$ |
| **Total** | **2** | |

---
6
\begin{enumerate}[label=(\alph*)]
\item Expand $( 5 + h ) ^ { 3 }$.
\item A curve has equation $y = x ^ { 3 } - x ^ { 2 }$.
\begin{enumerate}[label=(\roman*)]
\item Find the gradient of the line passing through the point $( 5,100 )$ and the point on the curve for which $x = 5 + h$. Give your answer in the form

$$p + q h + r h ^ { 2 }$$

where $p , q$ and $r$ are integers.
\item Show how the answer to part (b)(i) can be used to find the gradient of the curve at the point $( 5,100 )$. State the value of this gradient.
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{AQA FP1 2011 Q6 [7]}}