AQA FP1 2009 June — Question 1 7 marks

Exam BoardAQA
ModuleFP1 (Further Pure Mathematics 1)
Year2009
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicRoots of polynomials
TypeQuadratic with transformed roots
DifficultyStandard +0.3 This is a standard Further Maths roots question requiring straightforward application of sum/product formulas and root transformation. Part (a) is direct recall, part (b) uses the identity α²+β²=(α+β)²-2αβ, and part (c) applies standard transformation techniques. While it's Further Maths content, the execution is mechanical with no novel insight required, making it slightly easier than average overall.
Spec4.05a Roots and coefficients: symmetric functions4.05b Transform equations: substitution for new roots

1 The equation $$2 x ^ { 2 } + x - 8 = 0$$ has roots \(\alpha\) and \(\beta\).
  1. Write down the values of \(\alpha + \beta\) and \(\alpha \beta\).
  2. Find the value of \(\alpha ^ { 2 } + \beta ^ { 2 }\).
  3. Find a quadratic equation which has roots \(4 \alpha ^ { 2 }\) and \(4 \beta ^ { 2 }\). Give your answer in the form \(x ^ { 2 } + p x + q = 0\), where \(p\) and \(q\) are integers.

Question 1:
Part (a)
AnswerMarks
\(\alpha + \beta = -\frac{1}{2}\)B1
\(\alpha\beta = -4\)B1
Part (b)
AnswerMarks Guidance
\(\alpha^2 + \beta^2 = (\alpha+\beta)^2 - 2\alpha\beta\)M1 Use of correct identity
\(= (-\frac{1}{2})^2 - 2(-4) = \frac{1}{4} + 8 = \frac{33}{4}\)A1
Part (c)
AnswerMarks
Sum of new roots \(= 4\alpha^2 + 4\beta^2 = 4(\alpha^2+\beta^2) = 4 \times \frac{33}{4} = 33\)M1
Product of new roots \(= 4\alpha^2 \times 4\beta^2 = 16(\alpha\beta)^2 = 16 \times 16 = 256\)M1
\(x^2 - 33x + 256 = 0\)A1
# Question 1:

## Part (a)
| $\alpha + \beta = -\frac{1}{2}$ | B1 | |
| $\alpha\beta = -4$ | B1 | |

## Part (b)
| $\alpha^2 + \beta^2 = (\alpha+\beta)^2 - 2\alpha\beta$ | M1 | Use of correct identity |
| $= (-\frac{1}{2})^2 - 2(-4) = \frac{1}{4} + 8 = \frac{33}{4}$ | A1 | |

## Part (c)
| Sum of new roots $= 4\alpha^2 + 4\beta^2 = 4(\alpha^2+\beta^2) = 4 \times \frac{33}{4} = 33$ | M1 | |
| Product of new roots $= 4\alpha^2 \times 4\beta^2 = 16(\alpha\beta)^2 = 16 \times 16 = 256$ | M1 | |
| $x^2 - 33x + 256 = 0$ | A1 | |

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1 The equation

$$2 x ^ { 2 } + x - 8 = 0$$

has roots $\alpha$ and $\beta$.
\begin{enumerate}[label=(\alph*)]
\item Write down the values of $\alpha + \beta$ and $\alpha \beta$.
\item Find the value of $\alpha ^ { 2 } + \beta ^ { 2 }$.
\item Find a quadratic equation which has roots $4 \alpha ^ { 2 }$ and $4 \beta ^ { 2 }$. Give your answer in the form $x ^ { 2 } + p x + q = 0$, where $p$ and $q$ are integers.
\end{enumerate}

\hfill \mbox{\textit{AQA FP1 2009 Q1 [7]}}