AQA FP1 2007 June — Question 6 6 marks

Exam BoardAQA
ModuleFP1 (Further Pure Mathematics 1)
Year2007
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStandard trigonometric equations
TypeGeneral solution — find all solutions
DifficultyModerate -0.3 This is a straightforward trig equation requiring knowledge of the general solution formula and special angle values. While it's Further Maths (FP1), it only involves applying sin⁻¹(√3/2) = π/3 and the standard general solution sin(θ) = k gives θ = nπ + (-1)ⁿα, then solving for x. It's slightly easier than average due to being a direct application with a special angle and no algebraic manipulation needed.
Spec1.05o Trigonometric equations: solve in given intervals

6 Find the general solution of the equation $$\sin \left( 2 x - \frac { \pi } { 2 } \right) = \frac { \sqrt { 3 } } { 2 }$$ giving your answer in terms of \(\pi\).

AnswerMarks Guidance
One value of \(2x - \frac{\pi}{2} = \frac{\pi}{3}\)B1 OE (PI); degrees/decimals penalised in 6th mark only
Another value is \(\pi - \frac{\pi}{3} = \frac{2\pi}{3}\)B1F OE (PI); ft wrong first value
Introduction of \(2n\pi\) or \(n\pi\)M1
General solution for \(x\)m1
GS: \(x = \frac{5\pi}{12} + n\pi\) or \(x = \frac{7\pi}{12} + n\pi\)A2,1 OE; A1 if one part correct
Total: 6 marks
One value of $2x - \frac{\pi}{2} = \frac{\pi}{3}$ | B1 | OE (PI); degrees/decimals penalised in 6th mark only

Another value is $\pi - \frac{\pi}{3} = \frac{2\pi}{3}$ | B1F | OE (PI); ft wrong first value

Introduction of $2n\pi$ or $n\pi$ | M1 |
General solution for $x$ | m1 |

GS: $x = \frac{5\pi}{12} + n\pi$ or $x = \frac{7\pi}{12} + n\pi$ | A2,1 | OE; A1 if one part correct

**Total: 6 marks**

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6 Find the general solution of the equation

$$\sin \left( 2 x - \frac { \pi } { 2 } \right) = \frac { \sqrt { 3 } } { 2 }$$

giving your answer in terms of $\pi$.

\hfill \mbox{\textit{AQA FP1 2007 Q6 [6]}}