AQA FP1 2007 June — Question 5 11 marks

Exam BoardAQA
ModuleFP1 (Further Pure Mathematics 1)
Year2007
SessionJune
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicExponential Equations & Modelling
Typelog(y) vs x: convert and interpret
DifficultyModerate -0.3 This is a standard log-linearization question requiring routine application of logarithm laws to transform y = ab^x into Y = mx + c, followed by straightforward graph plotting and reading off intercept/gradient. While it involves multiple steps (4 parts), each step is mechanical with no novel insight required—slightly easier than average due to its cookbook nature.
Spec1.06h Logarithmic graphs: reduce y=ax^n and y=kb^x to linear form

5 [Figure 1 and Figure 2, printed on the insert, are provided for use in this question.] The variables \(x\) and \(y\) are known to be related by an equation of the form $$y = a b ^ { x }$$ where \(a\) and \(b\) are constants. The following approximate values of \(x\) and \(y\) have been found.
\(x\)1234
\(y\)3.846.149.8215.7
  1. Complete the table in Figure 1, showing values of \(x\) and \(Y\), where \(Y = \log _ { 10 } y\). Give each value of \(Y\) to three decimal places.
  2. Show that, if \(y = a b ^ { x }\), then \(x\) and \(Y\) must satisfy an equation of the form $$Y = m x + c$$
  3. Draw on Figure 2 a linear graph relating \(x\) and \(Y\).
  4. Hence find estimates for the values of \(a\) and \(b\).

AnswerMarks Guidance
(a) Values 0.788, 0.992, 1.196 in tableB2,1 B1 if one correct (or if wrong number of dp given)
(b) \(\lg ab^x = \lg a + \lg b^x\)M1
\(\lg b^x = x \lg b\)M1
So \(Y = (\lg b) x + \lg a\)A1 Allow NMS
Total: 3 marks
AnswerMarks
(c) Four points plotted; ft wrong values in (a)B1F
Good straight line drawn; ft incorrect pointsB1F
Total: 2 marks
AnswerMarks Guidance
(d) \(a = \) antilog of \(y\)-interceptM1A1
\(b = \) antilog of gradientM1A1 Accept 2.23 to 2.52; Accept 1.58 to 1.62
Total: 4 marks
**(a)** Values 0.788, 0.992, 1.196 in table | B2,1 | B1 if one correct (or if wrong number of dp given)

**(b)** $\lg ab^x = \lg a + \lg b^x$ | M1 |
$\lg b^x = x \lg b$ | M1 |
So $Y = (\lg b) x + \lg a$ | A1 | Allow NMS

**Total: 3 marks**

**(c)** Four points plotted; ft wrong values in (a) | B1F |
Good straight line drawn; ft incorrect points | B1F | 

**Total: 2 marks**

**(d)** $a = $ antilog of $y$-intercept | M1A1 |
$b = $ antilog of gradient | M1A1 | Accept 2.23 to 2.52; Accept 1.58 to 1.62

**Total: 4 marks**

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5 [Figure 1 and Figure 2, printed on the insert, are provided for use in this question.] The variables $x$ and $y$ are known to be related by an equation of the form

$$y = a b ^ { x }$$

where $a$ and $b$ are constants.

The following approximate values of $x$ and $y$ have been found.

\begin{center}
\begin{tabular}{ | c | c | c | c | c | }
\hline
$x$ & 1 & 2 & 3 & 4 \\
\hline
$y$ & 3.84 & 6.14 & 9.82 & 15.7 \\
\hline
\end{tabular}
\end{center}
\begin{enumerate}[label=(\alph*)]
\item Complete the table in Figure 1, showing values of $x$ and $Y$, where $Y = \log _ { 10 } y$. Give each value of $Y$ to three decimal places.
\item Show that, if $y = a b ^ { x }$, then $x$ and $Y$ must satisfy an equation of the form

$$Y = m x + c$$
\item Draw on Figure 2 a linear graph relating $x$ and $Y$.
\item Hence find estimates for the values of $a$ and $b$.
\end{enumerate}

\hfill \mbox{\textit{AQA FP1 2007 Q5 [11]}}