Edexcel M5 2007 June — Question 1 4 marks

Exam BoardEdexcel
ModuleM5 (Mechanics 5)
Year2007
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicWork done and energy
TypeWork done by constant force - vector setup
DifficultyStandard +0.3 This is a straightforward work-energy problem requiring calculation of displacement vector, dot product for work done, and application of work-energy theorem. All steps are standard M5 techniques with no conceptual challenges, making it slightly easier than average.
Spec1.10a Vectors in 2D: i,j notation and column vectors1.10b Vectors in 3D: i,j,k notation1.10c Magnitude and direction: of vectors6.02a Work done: concept and definition6.02b Calculate work: constant force, resolved component

  1. A bead of mass 0.5 kg is threaded on a smooth straight wire. The only forces acting on the bead are a constant force ( \(4 \mathbf { i } + 7 \mathbf { j } + 2 \mathbf { k }\) ) N and the normal reaction of the wire. The bead starts from rest at the point \(A\) with position vector \(( \mathbf { i } + 2 \mathbf { j } + 3 \mathbf { k } ) \mathrm { m }\) and moves to the point \(B\) with position vector \(( 4 \mathbf { i } + 3 \mathbf { j } - 2 \mathbf { k } ) \mathrm { m }\).
Find the speed of the bead when it reaches \(B\).
(4)

Question 1:
AnswerMarks Guidance
Working/AnswerMarks Guidance
\(\mathbf{d} = \mathbf{AB} = 3\mathbf{i} + \mathbf{j} - 5\mathbf{k}\)B1
\(\frac{1}{2}(0.5)v^2 = \mathbf{F}\cdot\mathbf{d} = (4\mathbf{i}+7\mathbf{j}+2\mathbf{k})\cdot(3\mathbf{i}+\mathbf{j}-5\mathbf{k})\)M1 A1
\(v = 6 \text{ m s}^{-1}\)A1 (4)
## Question 1:

| Working/Answer | Marks | Guidance |
|---|---|---|
| $\mathbf{d} = \mathbf{AB} = 3\mathbf{i} + \mathbf{j} - 5\mathbf{k}$ | B1 | |
| $\frac{1}{2}(0.5)v^2 = \mathbf{F}\cdot\mathbf{d} = (4\mathbf{i}+7\mathbf{j}+2\mathbf{k})\cdot(3\mathbf{i}+\mathbf{j}-5\mathbf{k})$ | M1 A1 | |
| $v = 6 \text{ m s}^{-1}$ | A1 | **(4)** |

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\begin{enumerate}
  \item A bead of mass 0.5 kg is threaded on a smooth straight wire. The only forces acting on the bead are a constant force ( $4 \mathbf { i } + 7 \mathbf { j } + 2 \mathbf { k }$ ) N and the normal reaction of the wire. The bead starts from rest at the point $A$ with position vector $( \mathbf { i } + 2 \mathbf { j } + 3 \mathbf { k } ) \mathrm { m }$ and moves to the point $B$ with position vector $( 4 \mathbf { i } + 3 \mathbf { j } - 2 \mathbf { k } ) \mathrm { m }$.
\end{enumerate}

Find the speed of the bead when it reaches $B$.\\
(4)\\

\hfill \mbox{\textit{Edexcel M5 2007 Q1 [4]}}