Edexcel M4 2017 June — Question 7 13 marks

Exam BoardEdexcel
ModuleM4 (Mechanics 4)
Year2017
SessionJune
Marks13
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMoments
TypePotential energy with elastic strings/springs
DifficultyChallenging +1.8 This is a Further Maths M4 question requiring derivation of potential energy from elastic and gravitational components, then using calculus to find equilibrium. It involves multiple steps: calculating spring extension, elastic PE, gravitational PE for multiple bodies, differentiating to find equilibrium, and testing stability with second derivative. While systematic, it requires careful geometric reasoning and coordination of several mechanical concepts beyond standard A-level.
Spec6.02d Mechanical energy: KE and PE concepts6.02e Calculate KE and PE: using formulae6.02h Elastic PE: 1/2 k x^26.02i Conservation of energy: mechanical energy principle6.04d Integration: for centre of mass of laminas/solids

7. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{23e6a9ae-bf00-45a3-b462-e18760d9af45-24_655_890_239_529} \captionsetup{labelformat=empty} \caption{Figure 2}
\end{figure} Figure 2 shows four uniform rods, each of mass \(m\) and length \(2 a\). The rods are freely hinged at their ends to form a rhombus \(A B C D\). Point \(A\) is attached to a fixed point on a ceiling and the rhombus hangs freely with \(C\) vertically below \(A\). A light elastic spring of natural length \(2 a\) and modulus of elasticity \(7 m g\) connects the points \(A\) and \(C\). A particle of mass \(3 m\) is attached to point \(C\).
  1. Show that, when \(A D\) is at an angle \(\theta\) to the downward vertical, the potential energy \(V\) of the system is given by $$V = 28 m g a \cos ^ { 2 } \theta - 48 m g a \cos \theta + \text { constant }$$ Given that \(\theta > 0\)
  2. find the value of \(\theta\) for which the system is in equilibrium,
  3. determine the stability of this position of equilibrium.

7.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{23e6a9ae-bf00-45a3-b462-e18760d9af45-24_655_890_239_529}
\captionsetup{labelformat=empty}
\caption{Figure 2}
\end{center}
\end{figure}

Figure 2 shows four uniform rods, each of mass $m$ and length $2 a$. The rods are freely hinged at their ends to form a rhombus $A B C D$. Point $A$ is attached to a fixed point on a ceiling and the rhombus hangs freely with $C$ vertically below $A$. A light elastic spring of natural length $2 a$ and modulus of elasticity $7 m g$ connects the points $A$ and $C$. A particle of mass $3 m$ is attached to point $C$.
\begin{enumerate}[label=(\alph*)]
\item Show that, when $A D$ is at an angle $\theta$ to the downward vertical, the potential energy $V$ of the system is given by

$$V = 28 m g a \cos ^ { 2 } \theta - 48 m g a \cos \theta + \text { constant }$$

Given that $\theta > 0$
\item find the value of $\theta$ for which the system is in equilibrium,
\item determine the stability of this position of equilibrium.
\end{enumerate}

\hfill \mbox{\textit{Edexcel M4 2017 Q7 [13]}}