| Exam Board | OCR |
|---|---|
| Module | M3 (Mechanics 3) |
| Year | 2008 |
| Session | June |
| Marks | 6 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Oblique and successive collisions |
| Type | Ball bouncing on horizontal surface |
| Difficulty | Standard +0.3 This is a standard M3 collision question requiring straightforward application of restitution formula and impulse-momentum theorem. Students resolve velocity into components, apply e=0.6 to the normal component, then calculate impulse from momentum change. It's slightly easier than average because it follows a textbook template with no conceptual surprises, though it requires careful component resolution. |
| Spec | 6.03j Perfectly elastic/inelastic: collisions |
2 A particle $P$ of mass 0.2 kg is moving with speed $8 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ when it hits a horizontal smooth surface. The direction of motion of $P$ immediately before impact makes an angle of $27 ^ { \circ }$ with the surface. Given that the coefficient of restitution between the particle and the surface is 0.6 , find\\
(i) the vertical component of the velocity of $P$ immediately after impact,\\
(ii) the magnitude of the impulse exerted on $P$.
\hfill \mbox{\textit{OCR M3 2008 Q2 [6]}}