CAIE P3 2020 June — Question 5 8 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2020
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPolynomial Division & Manipulation
TypeIntegration Using Polynomial Division
DifficultyStandard +0.3 This is a straightforward two-part question requiring polynomial long division followed by term-by-term integration. Part (a) is mechanical division, and part (b) involves integrating a polynomial plus a simple rational function (resulting in ln and arctan terms). While it requires multiple techniques, each step follows standard procedures with no novel insight needed, making it slightly easier than average.
Spec1.02j Manipulate polynomials: expanding, factorising, division, factor theorem1.08j Integration using partial fractions

5
  1. Find the quotient and remainder when \(2 x ^ { 3 } - x ^ { 2 } + 6 x + 3\) is divided by \(x ^ { 2 } + 3\).
  2. Using your answer to part (a), find the exact value of \(\int _ { 1 } ^ { 3 } \frac { 2 x ^ { 3 } - x ^ { 2 } + 6 x + 3 } { x ^ { 2 } + 3 } \mathrm {~d} x\).

Question 5(a):
AnswerMarks Guidance
AnswerMark Guidance
Commence division and reach quotient of the form \(2x + k\)M1
Obtain quotient \(2x - 1\)A1
Obtain remainder \(6\)A1
Question 5(b):
AnswerMarks Guidance
AnswerMark Guidance
Obtain terms \(x^2 - x\)B1FT FT on quotient of the form \(2x+k\)
Obtain term of the form \(a\tan^{-1}\left(\dfrac{x}{\sqrt{3}}\right)\)M1
Obtain term \(\dfrac{6}{\sqrt{3}}\tan^{-1}\left(\dfrac{x}{\sqrt{3}}\right)\)A1FT FT on a constant remainder
Use \(x=1\) and \(x=3\) as limits in a solution containing a term of the form \(a\tan^{-1}(bx)\)M1
Obtain final answer \(\dfrac{1}{\sqrt{3}}\pi + 6\), or exact equivalentA1
## Question 5(a):

| Answer | Mark | Guidance |
|--------|------|----------|
| Commence division and reach quotient of the form $2x + k$ | M1 | |
| Obtain quotient $2x - 1$ | A1 | |
| Obtain remainder $6$ | A1 | |

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## Question 5(b):

| Answer | Mark | Guidance |
|--------|------|----------|
| Obtain terms $x^2 - x$ | B1FT | FT on quotient of the form $2x+k$ |
| Obtain term of the form $a\tan^{-1}\left(\dfrac{x}{\sqrt{3}}\right)$ | M1 | |
| Obtain term $\dfrac{6}{\sqrt{3}}\tan^{-1}\left(\dfrac{x}{\sqrt{3}}\right)$ | A1FT | FT on a constant remainder |
| Use $x=1$ and $x=3$ as limits in a solution containing a term of the form $a\tan^{-1}(bx)$ | M1 | |
| Obtain final answer $\dfrac{1}{\sqrt{3}}\pi + 6$, or exact equivalent | A1 | |

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5
\begin{enumerate}[label=(\alph*)]
\item Find the quotient and remainder when $2 x ^ { 3 } - x ^ { 2 } + 6 x + 3$ is divided by $x ^ { 2 } + 3$.
\item Using your answer to part (a), find the exact value of $\int _ { 1 } ^ { 3 } \frac { 2 x ^ { 3 } - x ^ { 2 } + 6 x + 3 } { x ^ { 2 } + 3 } \mathrm {~d} x$.
\end{enumerate}

\hfill \mbox{\textit{CAIE P3 2020 Q5 [8]}}