CAIE P3 2020 June — Question 8 9 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2020
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicDifferential equations
TypeGeometric curve properties
DifficultyStandard +0.3 This is a straightforward separable differential equation requiring standard integration techniques. Setting up dy/dx = k·y/(x√x), separating variables, integrating (using ln y and x^(1/2)), then applying two boundary conditions to find constants k and C is methodical but routine. Part (b) requires simple limit analysis of the exponential form. Slightly above average due to the two-condition setup and fractional power integration, but still a standard textbook exercise.
Spec1.07t Construct differential equations: in context1.08k Separable differential equations: dy/dx = f(x)g(y)

8 A certain curve is such that its gradient at a point \(( x , y )\) is proportional to \(\frac { y } { x \sqrt { x } }\). The curve passes through the points with coordinates \(( 1,1 )\) and \(( 4 , \mathrm { e } )\).
  1. By setting up and solving a differential equation, find the equation of the curve, expressing \(y\) in terms of \(x\).
  2. Describe what happens to \(y\) as \(x\) tends to infinity.

Question 8(a):
AnswerMarks Guidance
AnswerMark Guidance
State \(\dfrac{dy}{dx} = k\dfrac{y}{x\sqrt{x}}\), or equivalentB1
Separate variables correctly and attempt integration of at least one sideM1
Obtain term \(\ln y\), or equivalentA1
Obtain term \(-2k\dfrac{1}{\sqrt{x}}\), or equivalentA1
Use given coordinates to find \(k\) or constant of integration \(c\) in a solution containing terms of the form \(a\ln y\) and \(\dfrac{b}{\sqrt{x}}\), where \(ab\neq 0\)M1
Obtain \(k=1\) and \(c=2\)A1+A1
Obtain final answer \(y = \exp\!\left(-\dfrac{2}{\sqrt{x}}+2\right)\), or equivalentA1
Question 8(b):
AnswerMarks Guidance
AnswerMark Guidance
State that \(y\) approaches \(e^2\)B1FT FT their \(c\) in part (a) of the correct form
## Question 8(a):

| Answer | Mark | Guidance |
|--------|------|----------|
| State $\dfrac{dy}{dx} = k\dfrac{y}{x\sqrt{x}}$, or equivalent | B1 | |
| Separate variables correctly and attempt integration of at least one side | M1 | |
| Obtain term $\ln y$, or equivalent | A1 | |
| Obtain term $-2k\dfrac{1}{\sqrt{x}}$, or equivalent | A1 | |
| Use given coordinates to find $k$ or constant of integration $c$ in a solution containing terms of the form $a\ln y$ and $\dfrac{b}{\sqrt{x}}$, where $ab\neq 0$ | M1 | |
| Obtain $k=1$ and $c=2$ | A1+A1 | |
| Obtain final answer $y = \exp\!\left(-\dfrac{2}{\sqrt{x}}+2\right)$, or equivalent | A1 | |

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## Question 8(b):

| Answer | Mark | Guidance |
|--------|------|----------|
| State that $y$ approaches $e^2$ | B1FT | FT their $c$ in part (a) of the correct form |

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8 A certain curve is such that its gradient at a point $( x , y )$ is proportional to $\frac { y } { x \sqrt { x } }$. The curve passes through the points with coordinates $( 1,1 )$ and $( 4 , \mathrm { e } )$.
\begin{enumerate}[label=(\alph*)]
\item By setting up and solving a differential equation, find the equation of the curve, expressing $y$ in terms of $x$.
\item Describe what happens to $y$ as $x$ tends to infinity.
\end{enumerate}

\hfill \mbox{\textit{CAIE P3 2020 Q8 [9]}}