CAIE P2 2018 November — Question 1 4 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2018
SessionNovember
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicInequalities
TypeSolve absolute value inequality
DifficultyStandard +0.3 This is a straightforward absolute value inequality requiring case analysis (considering signs of expressions inside absolute values) and solving linear inequalities. While it requires systematic work through multiple cases, the technique is standard A-level fare with no conceptual surprises, making it slightly easier than average.
Spec1.02l Modulus function: notation, relations, equations and inequalities

1 Solve the inequality \(| 3 x - 5 | < 2 | x |\).

Question 1:
Either method:
AnswerMarks Guidance
AnswerMarks Guidance
State or imply non-modular inequality \((3x-5)^2 < 4x^2\) or corresponding equation or pair of linear equationsB1 SC: Common error \((3x-5)^2 < 2x^2\)
Attempt solution of 3-term quadratic equation or solution of 2 linear equationsM1
Obtain critical values 1 and 5A1 Critical values \(\frac{15 \pm 5\sqrt{2}}{7}\) or 3.15, 1.13 allow B1
State correct answer \(1 < x < 5\)A1 \(\frac{15-5\sqrt{2}}{7} < x < \frac{15+5\sqrt{2}}{7}\) or \(1.13 < x < 3.15\) B1; Max 2/4; Allow M1 for \((7x \pm 5)(x \pm 5)\)
Or method:
AnswerMarks Guidance
AnswerMarks Guidance
Obtain \(x = 5\) by solving linear equation or inequality or from graphical method or inspectionB1 Allow B1 for 5 seen, maybe in an inequality
Obtain \(x = 1\) similarlyB2 Allow B2 for 1 seen, maybe in an inequality
State correct answer \(1 < x < 5\)B1
Total4
**Question 1:**

**Either method:**

| Answer | Marks | Guidance |
|--------|-------|----------|
| State or imply non-modular inequality $(3x-5)^2 < 4x^2$ or corresponding equation or pair of linear equations | **B1** | SC: Common error $(3x-5)^2 < 2x^2$ |
| Attempt solution of 3-term quadratic equation or solution of 2 linear equations | **M1** | |
| Obtain critical values 1 and 5 | **A1** | Critical values $\frac{15 \pm 5\sqrt{2}}{7}$ or 3.15, 1.13 allow B1 |
| State correct answer $1 < x < 5$ | **A1** | $\frac{15-5\sqrt{2}}{7} < x < \frac{15+5\sqrt{2}}{7}$ or $1.13 < x < 3.15$ B1; Max 2/4; Allow M1 for $(7x \pm 5)(x \pm 5)$ |

**Or method:**

| Answer | Marks | Guidance |
|--------|-------|----------|
| Obtain $x = 5$ by solving linear equation or inequality or from graphical method or inspection | **B1** | Allow B1 for 5 seen, maybe in an inequality |
| Obtain $x = 1$ similarly | **B2** | Allow B2 for 1 seen, maybe in an inequality |
| State correct answer $1 < x < 5$ | **B1** | |
| **Total** | **4** | |
1 Solve the inequality $| 3 x - 5 | < 2 | x |$.\\

\hfill \mbox{\textit{CAIE P2 2018 Q1 [4]}}