CAIE P2 2018 November — Question 6 11 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2018
SessionNovember
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStandard Integrals and Reverse Chain Rule
TypeUse trig identity before definite integration
DifficultyStandard +0.3 Part (a) is a straightforward logarithmic integration requiring simple substitution or recognition of the standard form. Part (b) requires knowing the identities sin²x = (1-cos2x)/2 and tan²2x = sec²2x - 1, then integrating standard forms. While it involves multiple identities and careful manipulation, these are well-practiced techniques at A-level with no novel problem-solving required, making it slightly easier than average.
Spec1.05j Trigonometric identities: tan=sin/cos and sin^2+cos^2=11.05k Further identities: sec^2=1+tan^2 and cosec^2=1+cot^21.06f Laws of logarithms: addition, subtraction, power rules1.08c Integrate e^(kx), 1/x, sin(kx), cos(kx)

6
  1. Show that \(\int _ { 1 } ^ { 6 } \frac { 12 } { 3 x + 2 } \mathrm {~d} x = \ln 256\).
  2. Find the exact value of \(\int _ { 0 } ^ { \frac { 1 } { 6 } \pi } \left( 8 \sin ^ { 2 } x + \tan ^ { 2 } 2 x \right) \mathrm { d } x\), showing all necessary working.

Question 6(a):
AnswerMarks Guidance
AnswerMark Guidance
Integrate to obtain form \(k\ln(3x+2)\)\*M1 Condone poor use of brackets if recovered later
Obtain correct \(4\ln(3x+2)\)A1
Substitute limits correctlyM1 Dependent \*M, must see \(k\ln 20-k\ln 5\) oe
Apply relevant logarithm properties correctlyM1 Dependent \*M, do not allow \(\frac{4\ln 20}{4\ln 5}\) oe, must be using both the subtraction and power laws correctly
Obtain \(\ln 256\) nfwwA1 AG; necessary detail needed
Question 6(b):
AnswerMarks Guidance
AnswerMark Guidance
Use identity to obtain \(4(1-\cos 2x)\) oeB1
Use identity to obtain \(\sec^2 2x-1\)B1
Integrate to obtain form \(k_1x+k_2\sin 2x+k_3\tan 2x\)\*M1 Allow M1 if integrand contains \(p\cos 2x+q\sec^2 2x\) and no other trig terms
Obtain correct \(3x-2\sin 2x+\frac{1}{2}\tan 2x\)A1
Apply limits correctly retaining exactnessM1 Dependent \*M, allow \(\sin\frac{\pi}{3}\), \(\tan\frac{\pi}{3}\)
Obtain \(\frac{1}{2}\pi-\frac{1}{2}\sqrt{3}\) or exact equivalentA1
## Question 6(a):

| Answer | Mark | Guidance |
|--------|------|----------|
| Integrate to obtain form $k\ln(3x+2)$ | \*M1 | Condone poor use of brackets if recovered later |
| Obtain correct $4\ln(3x+2)$ | A1 | |
| Substitute limits correctly | M1 | Dependent \*M, must see $k\ln 20-k\ln 5$ oe |
| Apply relevant logarithm properties correctly | M1 | Dependent \*M, do not allow $\frac{4\ln 20}{4\ln 5}$ oe, must be using both the subtraction and power laws correctly |
| Obtain $\ln 256$ nfww | A1 | AG; necessary detail needed |

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## Question 6(b):

| Answer | Mark | Guidance |
|--------|------|----------|
| Use identity to obtain $4(1-\cos 2x)$ oe | B1 | |
| Use identity to obtain $\sec^2 2x-1$ | B1 | |
| Integrate to obtain form $k_1x+k_2\sin 2x+k_3\tan 2x$ | \*M1 | Allow M1 if integrand contains $p\cos 2x+q\sec^2 2x$ and no other trig terms |
| Obtain correct $3x-2\sin 2x+\frac{1}{2}\tan 2x$ | A1 | |
| Apply limits correctly retaining exactness | M1 | Dependent \*M, allow $\sin\frac{\pi}{3}$, $\tan\frac{\pi}{3}$ |
| Obtain $\frac{1}{2}\pi-\frac{1}{2}\sqrt{3}$ or exact equivalent | A1 | |
6
\begin{enumerate}[label=(\alph*)]
\item Show that $\int _ { 1 } ^ { 6 } \frac { 12 } { 3 x + 2 } \mathrm {~d} x = \ln 256$.
\item Find the exact value of $\int _ { 0 } ^ { \frac { 1 } { 6 } \pi } \left( 8 \sin ^ { 2 } x + \tan ^ { 2 } 2 x \right) \mathrm { d } x$, showing all necessary working.
\end{enumerate}

\hfill \mbox{\textit{CAIE P2 2018 Q6 [11]}}